我有一个小数据集
SELECT PID, PCODE, PVAL
FROM mytable
输出:
PID PCODE PVAL
2 N50 £1,000.00
2 B10 £100.00
2 P40 £500.00
3 B10 £100.00
3 P40 £500.00
4 B10 £100.00
4 P40 £500.00
我想输出相同的字段,除非PID组的PCODE为N50,那么它们的B10需要像N50一样减少5%。
预期产出:
PID PCODE PVAL
2 N50 £1,000.00
2 B10 £50.00
2 P40 £500.00
3 B10 £100.00
3 P40 £500.00
4 B10 £100.00
4 P40 £500.00
我已尝试使用子查询和case语句,但无法获得匹配的值。
答案 0 :(得分:1)
您可以使用分析函数执行此操作:
SELECT PID, PCODE,
(PVAL -
COALESCE(SUM(CASE WHEN PCODE = 'N50' THEN PVAL * 0.05 END) OVER (PARTITION BY PID), 0)
) as PVAL
FROM mytable;
实际上,COALESCE()
不是必需的:
SELECT PID, PCODE,
(PVAL -
SUM(CASE WHEN PCODE = 'N50' THEN PVAL * 0.05 ELSE 0 END) OVER (PARTITION BY PID)
) as PVAL
FROM mytable;
答案 1 :(得分:1)
您可以使用case
表达式和max
函数来执行此操作。这假设pid只能有一行pcode = N50。
select pid,pcode
,case when pcode='B10' then pval-0.05*max(case when pcode='N50' then pval else 0 end) over(partition by pid)
else pval end as pval
from mytable t
编辑:将结果限制为包含B10代码的年份的一种方法是
select pid,pcode
,case when pcode='B10' then pval-0.05*max(case when pcode='N50' then pval else 0 end) over(partition by pid)
else pval end as pval
from mytable t
where yearcolumn in (select yearcolumn from mytable where pcode='B10')
答案 2 :(得分:1)
此解决方案仅在主表具有“B10”且第二个表具有“N50”时才使用左连接来获得匹配。 如果匹配:返回PVAL折扣5%的N50 PVAL。 如果不匹配:返回PVAL
SELECT t1.PID, T1.PCODE, t1.PVAL - isnull( .05 * t2.PVAL, 0) PVAL
FROM mytable t1
left join #mytable t2
on t1.PID = t2.PID and t1.PCode = 'B10' and t2.PCode = 'N50'