正则表达式 - 将数字和字符串的组合替换为另一个字符串

Question

我需要用[替换字符串]

替换所有[任意数字]和[特定字符串]

例如，如果在段落中找到 195 apples 或 10 apples 等字符串，我需要将其替换为 10 Oranges

示例段落：第一个篮子里有195个苹果，第二个篮子里有10个苹果。

应用正则表达式替换后，我应该得到一个结果 结果：第一个篮子里有10个橘子，第二个篮子里有10个橘子。

在Jquery中，我使用了

 myString.replaceAll("[(?i)string]", "anotherstring"); 

需要在PHP和Jquery中执行此操作。

任何人都可以帮助我吗？感谢

Answer 1

怎么样：

＆＃13;

＆＃13;

 
 var myString = 'There are 195 apples in the first basket and 10 apples in the second basket.';
myString = myString.replace("/(?i)\d+\s+apples\b/g", "10 Oranges");
console.log(myString);

＆＃13;

＆＃13;

＆＃13;

Answer 2

搜索\d{1,}\s+(apples)

替换10 Oranges

Answer 3

尝试使用以下正则表达式：

(\d+\s(\w+))

** 您可以将\w+替换为所需的字符串

请参阅demo / explanation

<强>的JavaScript

var str = "There are 195 apples in the first basket and 10 apples in the second basket.";
var result = str.replace(/(\d+\s(\w+))/ig, "10 Oranges");
console.log(result);

<强> PHP

$re = '/(\d+\s(\w+))/';
$str = 'There are 195 apples in the first basket and 10 apples in the second basket.';
$subst = '10 Oranges';
$result = preg_replace($re, $subst, $str);
echo $result;

Answer 4

这有效

PHP

$re = '/(\d+\s((apples\b|apple\b)+))/';
$str = '195 apples in the first basket and 0 apple but 1 applex';
$subst = '10 Oranges';
$result = preg_replace($re, $subst, $str);
echo $result;

JQuery

var text1 = "10 apples is good";
var rrr = "10 Oranges";
var str = "There are 195 apple in the first basket and 10 apples in the second basket.1 apple";
var result = str.replace(/(\d+\s((apples\b|apple\b)+))/ig,"10 Oranges");
console.log(result);