我有两个表类别和子类别。在类别表中,我有一列cat_url.In子类别表,我有一列sub_cat_url
我想要的是获取按字母顺序排序的类别表和子类别表的所有URL并在菜单下拉菜单中显示
我在做的是:
$A = "SELECT cat_url FROM category
WHERE cat_url like 'a%'
UNION ALL
SELECT sub_cat_url FROM subcategory
WHERE sub_cat_url like 'a%'
ORDER BY cat_url, sub_cat_url";
$rA = mysqli_query($dbc,$A) or die(mysqli_error($dbc));
while ($rsA = mysqli_fetch_assoc($rA)){
<a href=".$rsA['cat_url'].'.php'.">
echo $rsA['cat_url'];
// i do not want to use $rsA['cat_url']; What i need is to combine both cat_url and sub_cat_url in one result set and the echo each url
}
答案 0 :(得分:1)
尝试以下查询:
select *
from (
SELECT cat_url as url FROM category WHERE cat_url like 'a%'
union all
SELECT sub_cat_url as url FROM subcategory WHERE sub_cat_url like 'a%'
) a
order by url
答案 1 :(得分:0)
您可以尝试加入子类别表(未经测试):
SELECT cat.cat_url as cat_url, subcat.sub_cat_url as sub_cat_url FROM category as cat
left join subcategory as subcat on subcat.sub_cat_url like 'a%'
WHERE cat.cat_url like 'a%'
ORDER BY cat.cat_url, subcat.sub_cat_url