Question

大家好，我正在研究某种会计系统，遇到了一些困难。阿卜杜勒·拉希德已经在这个网站上回答了这个问题。

这是代码

declare @sDate datetime,
    @eDate datetime

select @sDate = '2013-02-21',
    @eDate = '2013-04-25';

with CTE_TEST
as (
    select @sDate SDATE,
        DATEADD(s, - 1, DATEADD(mm, DATEDIFF(m, 0, @sDate) + 1, 0)) EDATE

    union all

    select EDATE + 1,
        DATEADD(s, - 1, DATEADD(mm, DATEDIFF(m, 0, DATEADD(MONTH, 1, SDATE)) + 1, 0))
    from CTE_TEST C
    where DATEADD(MONTH, 1, SDATE) < DATEADD(s, - 1, DATEADD(mm, DATEDIFF(m, 0, @eDate) + 1, 0))
    )
select DATENAME(MONTH, SDATE) MNAME,
    SDATE, (case when EDATE > @eDate then @eDate else EDATE end) EDATE
from CTE_TEST

代码很有效，就像我想要的那样。但我想将结果插入到新表中。我该怎么做？

Answer 1

CREATE TABLE T(MNAME VARCHAR(20),SDATE DATETIME,EDATE DATETIME)  

      IF OBJECT_ID ('tempdb..#T') IS NOT  NULL
        DROP TABLE #T

          declare @sDate datetime,
            @eDate datetime
            select  @sDate = '2013-02-21',
            @eDate = '2013-04-25'
            ;WITH CTE_TEST AS (
            SELECT @sDate SDATE,DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@sDate)+1,0)) EDATE
            UNION ALL
            SELECT  EDATE+1,DATEADD(s,-1,DATEADD(mm,DATEDIFF(m,0,DATEADD(MONTH,1,SDATE))+1,0))
            FROM    CTE_TEST C WHERE DATEADD(MONTH,1,SDATE) <   DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@eDate)+1,0))
    )   
             SELECT DATENAME(MONTH,SDATE) MNAME,SDATE,(CASE WHEN EDATE > @eDate THEN  @eDate ELSE EDATE END) EDATE INTO #T FROM CTE_TEST 



INSERT INTO T(  MNAME,
                SDATE,
                EDATE)
Select MNAME,
SDATE,
EDATE from #T

如何获取sql server中两个日期之间的开始日期和结束日期

1 个答案: