Question

mysql查询在mysql中执行但在mysqli和mysql中没有被弃用，所以我必须在codeigniter中使用mysqli的语法：

 $sql = "SELECT admin_email
                FROM `tbl_admin`
                WHERE `admin_email` = '" . $username . "' and `admin_password` = '" . $password . "'"; 
        $query = $this->db->query($sql);

Answer 1

您可以使用Codeigniter Query Bulider

$this->db->select('admin_email');
$this->db->from('tbl_admin');
$this->db->where('admin_email', $username);
$this->db->where('admin_password', $password);
$query = $this->db->get();

Answer 2

我希望它有效......

$this->db->select('*');
$this->db->from('tbl_admin');
$this->db->where('admin_email', $username);
$this->db->where('admin_password', $password);

$query = $this->db->get();
$result = $query->row();

return $result;

Answer 3

尝试......

 $this->db->select('admin_email');
 $this->db->where(
             array(
                'admin_email' => $username,
                'admin_password' => $password
             ));
 $query = $this->db->get('tbl_admin');
 $result = $query->row();

希望它能在你的作品中发挥作用......

Answer 4

$this->db->where('admin_email',$email);
$this->db->where('admin_password',$password);
$qry = $this->db->get('tbl_admin');
if($qry->num_rows() > 0){
    return true;
}else{
    return false;
}

Answer 5

仅当您在模型中设置查询然后在控制器中加载该模型时，该方法才能正常工作。直接从Controller设置查询似乎有此问题。

示例：通过模型：示例“ Users.php”

class Users extends CI_Model {

    public function __construct() {
        parent::__construct();
    }

    function check_username($username) {
            $query = $this->db->query("select * from `user_login` where `username`='$username'")
            $query_result = $query->result_array;
            if (!empty($query_result)) {
                return $query_result;
            }
            return[];
        }
}

在控制器中：示例“ Userauth.php”

class Userauth extends CI_Controller {
public function process_forgot(){
        $CI =& get_instance();
        $CI->load->model('Users'); //Model loaded here
        $username = $this->input->post('username');
        $check = $CI->Users->check_username($username);
        echo '<pre>';
        print_r($check);
        echo '</pre>';
    }
}

尝试一下。

在codeigniter中选择不使用mysqli的查询

5 个答案: