Question

运行python 3.0

我收到一个“AttributeError：'tuple'对象没有属性替换”错误代码基于三个函数来处理更高的数字（超过100万）。不幸的是，函数似乎没有执行，因为元组导致a（）。

功能代码 -

def under_ten_million(value):                                       #     under 10000000
    textnumber = str(test_n)
    firstdigit, secondDigit, thirdDigit, fourthdigit, fifthdigit, sixthdigit, seventhdigit = textnumber
    words.append(million_list[int(firstdigit)])
    if int(sixthdigit) >= 2:
        words.append(hundreds_list[int(secondDigit)])
        words.append(decades_list[int(thirdDigit)-1])
        words.append(thousand_list[int(fourthdigit)])
        words.append(hundreds_list[int(fifthdigit)])
        words.append(decades_list[int(sixthdigit)-1])
        words.append(number_list[int(seventhdigit)])
    elif int(sixthdigit) < 2:
        words.append(hundreds_list[int(secondDigit)])
        words.append(decades_list[int(thirdDigit)-1])
        words.append(thousand_list[int(fourthdigit)])
        words.append(hundreds_list[int(fifthdigit)])
        if int(sixthdigit + seventhdigit) == 10:
            words.append(teen_list[1])
            words.append(number_list[0])
        elif int(sixthdigit + seventhdigit) > 10:
            words.append(teen_list[int(seventhdigit)+1])
            words.append(number_list[0])
    return words

（整个代码的要点是输入数字并输出所述数字的字值。我正在使用基于if语句中的输入数字使用的实现函数来执行此操作。示例如何程序运行 - 输入= 345942，输出=三十四万五千九百四十二）

正如您在下面根据打印代码看到的那样，我仍然在“under_ten_million”下面还有2个相同的代码（只有1或2个额外的行来修改新数字）。

试图打印结果的代码部分 -

# Tests where the number lies in terms of function use, then provides correct function.

string_of_words = ()

if n <= 10:
    under_ten(n)
    string_of_words = words[0]
elif 10 < n < 100:
    under_hundred(n)
    string_of_words = words[0] + " " + words[1]
elif 100 < n < 1000:
    under_thousand(n)
    string_of_words = words[0] + " " + words[1] + " " + words[2]
elif 1000 < n < 10000:
    under_ten_thousand(n)
    string_of_words = words[0] + " " + words[1] + " " + words[2] + " " + words[3]
elif 10000 < n < 100000:
    under_hundred_thousand(n)
    string_of_words = words[0] + " " + words[1] + " " + words[2] + " " + words[3] + " " + words[4]
elif 100000 < n < 1000000:
    under_million(n)
    string_of_words = words[0] + " " + words[1] + " " + words[2] + " " + words[3] + " " + words[4] + " " + words[5]
elif 10000000 < n < 100000000:
    under_ten_million(n)
    string_of_words = words[0] + " " + words[1] + " " + words[2] + " " + words[3] + " " + words[3] + " " + words[5] + " " + words[6]
elif 100000000 < n < 1000000000:
    under_hundred_million(n)
    string_of_words = words[0] + " " + words[1] + " " + words[2] + " " + words[3] + " " + words[4] + " " + words[5] + " " + words[6] + " " + words[7]
elif 1000000000 < n < 10000000000:
    under_billion(n)
    string_of_words = words [0] + " " + words[1] + " " + words[2] + " " + words[3] + " " + words[4] + " " + words[5] + " " + words[6] + " " + words[7] + " " + words[8]

print(string_of_words.replace(' zero', ''))

我有类似（基本相同）的功能完美地工作，这就是为什么我很困惑为什么超过100万的数字不计算。如果您想要整个代码（近250行），我也可以上传它！

谢谢！

功能没有运行？！？元组错误？

0 个答案: