Question

我有收藏集cars，registrations，car_specs

我需要创建两个新的集合

cars_registrations - 对于具有相同RegNo和registrations的文档，这会将cars从StreetNo添加到HouseNo，从而丢弃文档没有比赛。
cars_registrations_spec - 这会为CarSpec到car_specs集合添加cars_registrations，以查找具有相同StreetNo和HouseNo的文档。< / p>

从控制台执行此操作的最有效方法是什么？cars集合中有500K文档，registrations集合中有50K文档。

汽车：

[
        { "StreetNo": 321, "HouseNo": "12",  "Car": "camry" },
        { "StreetNo": 321, "HouseNo": "13",  "Car": "camry" },
        { "StreetNo": 323, "HouseNo": "12",  "Car": "accord" },
        { "StreetNo": 324, "HouseNo": "15",  "Car": "Sunny" }
    ]

注册

[
        { "StreetNo": 321, "HouseNo": "12",  "RegNo": "1122" },
        { "StreetNo": 321, "HouseNo": "13",  "RegNo": "1123" },
        { "StreetNo": 323, "HouseNo": "12",  "RegNo": "1124" },
    ]

cars_registrations

[
        { "StreetNo": 321, "HouseNo": "12",  "Car": "camry",  "RegNo": "1122"  },
        { "StreetNo": 321, "HouseNo": "13",  "Car": "camry",  "RegNo": "1123" },
        { "StreetNo": 323, "HouseNo": "12",  "Car": "accord",  "RegNo": "1124" }
    ]

car_specs

[
        { "StreetNo": 321, "HouseNo": "12",  "CarSpec": {"cyl": "4", "gear": "5"} },
        { "StreetNo": 321, "HouseNo": "13",  "CarSpec": {"cyl": "4", "gear": "5"} },
        { "StreetNo": 323, "HouseNo": "12",  "CarSpec": {"cyl": "6", "gear": "7"} }
    ]

cars_registrations_spec

[
        { "StreetNo": 321, "HouseNo": "12",  "Car": "camry",  "RegNo": "1122",  "CarSpec": {"cyl": "4", "gear": "5"} },
        { "StreetNo": 321, "HouseNo": "13",  "Car": "camry",  "RegNo": "1123",  "CarSpec": {"cyl": "4", "gear": "5"} },
        { "StreetNo": 323, "HouseNo": "12",  "Car": "accord", "RegNo": "1124", "CarSpec": {"cyl": "6", "gear": "7"} }
    ]

以下是一种尝试的方法。但是，这需要永远完成集合中的文档数量 - 这样做的mongodb way是什么？

for cars_registrations

var results = db.registrations.find({}, {_id: 0}).toArray();
for( var i = 0; i < results.length; i++) {
    var car = db.car.findOne({$and: [{StreetNo: results[i]["StreetNo"]},
    {HouseNo: results[i]["HouseNo"]}] }, {_id: 0});
    if(car && results[i]["RegNo"]) {
        car["RegNo"] = results[i]["RegNo"]
        db.cars_registrations.insertOne(car);
    }
}

我遇到的问题是它需要很长时间 - 很多小时 - 我的猜测findOne $and需要花费很多时间 - 对我来说需要花费很多时间在拥有500K文档和50K文档注册集合的汽车收藏中完成此操作。这通常花费这么多时间吗？

查找跨集合的匹配字段的文档，并从匹配的文档中添加新字段

0 个答案: