Question

我的项目模型如下所示：

# == Schema Information
# Schema version: 20101117094659
#
# Table name: projects
#
#  id          :integer         not null, primary key
#  name        :string(255)
#  description :string(255)
#  designer_id :integer
#  client_id   :integer
#  notified    :boolean
#  created_at  :datetime
#  updated_at  :datetime
#  user_id     :integer
#

class Project < ActiveRecord::Base

  belongs_to :user
  has_many :stages
  has_many :uploads
  has_many :comments

end

Projects Controller看起来像这样：

class ProjectsController < ApplicationController
  filter_resource_access

  # GET /projects
  # GET /projects.xml
  def index
    @projects = Project.all

    respond_to do |format|
      format.html # index.html.erb
      format.xml  { render :xml => @projects }
    end
  end

  # GET /projects/1
  # GET /projects/1.xml
  def show
    @project = Project.find(params[:id])

    respond_to do |format|
      format.html # show.html.erb
      format.xml  { render :xml => @project }
    end
  end

  # GET /projects/new
  # GET /projects/new.xml
  def new
    @project = Project.new

    respond_to do |format|
      format.html # new.html.erb
      format.xml  { render :xml => @project }
    end
  end

  # GET /projects/1/edit
  def edit
    @project = Project.find(params[:id])     
  end

  # POST /projects
  # POST /projects.xml
  def create
    @project = Project.new(params[:project])

    respond_to do |format|
      if @project.save
        format.html { redirect_to(@project, :notice => 'Project was successfully created.') }
        format.xml  { render :xml => @project, :status => :created, :location => @project }
      else
        format.html { render :action => "new" }
        format.xml  { render :xml => @project.errors, :status => :unprocessable_entity }
      end
    end
  end

  # PUT /projects/1
  # PUT /projects/1.xml
  def update
    @project = Project.find(params[:id])

    respond_to do |format|
      if @project.update_attributes(params[:project])
        format.html { redirect_to(@project, :notice => 'Project was successfully updated.') }
        format.xml  { head :ok }
      else
        format.html { render :action => "edit" }
        format.xml  { render :xml => @project.errors, :status => :unprocessable_entity }
      end
    end
  end

  # DELETE /projects/1
  # DELETE /projects/1.xml
  def destroy
    @project = Project.find(params[:id])    
    @project.destroy

    respond_to do |format|
      format.html { redirect_to(projects_url) }
      format.xml  { head :ok }
    end
  end
end

当用户登录并转到点击链接到项目控制器的索引操作的“查看所有项目”时，我希望他们只看到允许他们看到的项目。

项目控制器的索引视图如下所示：

<h1>Listing projects</h1>

<table>
  <tr>
    <th>Name</th>
    <th>Description</th>
    <th></th>
  </tr>

<% @projects.each do |project| %>
    <tr>
        <td><%= link_to project.name, project %> | </td>
        <td><%= project.description %> | </td>


        <% if permitted_to? :edit, @project %>
            <td><%= link_to 'Edit', edit_project_path(project) %></td>
        <% end %>

        <% if permitted_to? :destroy, @project %>
            <td><%= link_to 'Destroy', project, :confirm => 'Are you sure?', :method => :delete %></td>
        <% end %>
    </tr>
<% end %>
</table>

<br />

<% if permitted_to? :create, Project.new %>
    <%= link_to 'New Project', new_project_path %>
<% end %>

我不希望你为我这样做，但你可以和我一起走看我需要做的事情。即我是否需要向表中添加新列，或者我是否创建新表并在该新表与我的用户和项目模型之间创建联接。表？

要记住的另一件事是，我有四个主要模型，我想为每个用户个性化。项目，评论，上传，阶段。

哦，我有一个超级用户，我希望能够查看每个用户的所有项目/评论/阶段/上传（在粒度级别和高级别上）。

很想听听你的想法。

编辑：另外，如果你可以指出我可能会帮助我完成整个过程的一些阅读材料 - 我真的很感激。

Answer 1

您需要添加用户模型：

class User
  ...
  has_many :projects
end

这应该是诀窍：

@projects = current_user.projects

如果你当然有一个current_user方法，那将会有效。否则它相当于（虽然我确定你不想传递user_id）：

@projects = User.find(params[:id]).projects

您应该真正阅读rails tutorial book或rails guides

Answer 2

def index
  @projects = Project.find_by_user_id(HOWEVER YOU KEEP YOUR USER ID)
  respond_to do |format|
    format.html # index.html.erb
    format.xml  { render :xml => @projects }
  end
end

这项工作只有当用户只能看到他们自己创建的项目时，迈克回答。

如果您希望用户能够访问其他项目，那么他可以使用has_many :through association。表中包含用户ID和项目ID。

Answer 3

您需要在项目表中添加user_id，而不是使用上述建议

如何仅显示项目/评论/等。属于Rails 3中的用户？

3 个答案: