Question

目标：

有两张桌子，一张校友表和一份捐款表 - 每份捐款都与校友的ID有关
获取有校友的名单在该日期内贡献了2-3000 范围2002-10-10和2003-10-10。
结果需要显示校友的姓名，身份证，每位校友的历史总数，以及每位校友的总数。指定的日期范围

尝试：

SELECT alumni.alumni_id, alumni.alumni_name,
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id) AS contrib_alltime_total,
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) AS contrib_range_total

FROM alumni
WHERE hold_code IS NULL    
ORDER BY lname ASC    
HAVING contrib_range_total >= 2000
HAVING contrib_range_total <= 3000

我收到语法错误，很可能是因为我试图使用两个HAVING的

我也意识到你想使用带有GROUP BY的HAVING，但我不需要进行任何分组

我可能会这样做，但我认为它效率低，可能需要很长时间

SELECT alumni.alumni_id, alumni.alumni_name,
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id) AS contrib_alltime_total,
(SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) AS contrib_range_total

FROM alumni

WHERE hold_code IS NULL
AND (SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) >= 2000
AND (SELECT SUM(contributed_amt) FROM contribution WHERE contribution.alumni_id = alumni.alumni_id AND contribution.date >= 2002-10-10 AND contribution.date <= 2003-10-10) <= 3000

ORDER BY lname ASC

实现这一目标的最快，最有效的方法是什么？欢迎任何建议，谢谢你的时间

Answer 1

SELECT a.alumni_id, a.alumni_name, 
SUM(c.contributed_amt) AS contrib_alltime_total, 
SUM(c.contributed_amt) AS contrib_range_total

FROM alumni a, contribution c

WHERE a.hold_code IS NULL
AND c.alumni_id = a.alumni_id AND c.date BETWEEN '2002-10-10' AND '2003-10-10'
AND contrib_range_total BETWEEN 2000 AND 3000
ORDER BY lname ASC

Answer 2

我认为，如果没有HAVING，您就无法使用GROUP BY，并使用AND加入多个HAVING个案例......

GROUP BY contrib_range_total HAVING contrib_range_total >= 2000 AND contrib_range_total <= 3000

Answer 3

SELECT a.alumni_id,
sum(c.contributed_amt) AS contrib_alltime_total,
sum(case when c.contribution_date BETWEEN '2002-10-10' AND '2003-10-10' then c.contributed_amt else 0 end) AS contrib_range_total
FROM alumni a
INNER JOIN contribution c ON c.alumni_id = a.alumni_id
WHERE a.hold_code IS NULL
GROUP BY a.alumni_id
HAVING contrib_range_total BETWEEN 2000 AND 3000

MySQL Query有两个条件内联SELECT

3 个答案: