Question

根据需要，我需要将boost::posix_time::ptime转换为NTP 日期标记 RFC 5905由以下结构表示：

struct NtpDatestamp {
  std::int32_t era_number;
  std::uint32_t seconds_since_era_epoch;
  std::uint64_t fraction_of_second;
};

RFC 5905声明如下：

将任何格式的系统时间转换为NTP日期和时间戳格式要求从主要时期到系统的秒数s 时间确定。确定给定era的整数timestamp和s，
era = s / 2^(32) and timestamp = s - era * 2^(32),
适用于正面和负面日期。在给定时代的情况下确定s 和时间戳，
s = era * 2^(32) + timestamp.

因此我尝试了以下方法：

const auto system_time = boost::posix_time::time_from_string("1899-12-31 00:00:00.000");

const boost::posix_time::ptime prime_epoch{boost::gregorian::date{1900, 1, 1}};
// Calculate the number of seconds from the prime epoch to the system time.
const boost::posix_time::time_duration time_duration{system_time - prime_epoch};
const std::int64_t s{time_duration.total_seconds()};
const std::int32_t era_number{static_cast<std::int32_t>(s / std::pow(2, 32))};
const std::uint64_t seconds_since_era_epoch{static_cast<std::uint64_t>(s - s / std::pow(2, 32) * std::pow(2, 32))};
// The fraction of a NTP Datestamp is measured in Attoseconds.
const std::uint64_t fraction_of_second{static_cast<std::uint64_t>(time_duration.total_microseconds() * 1e12)};

但这会产生不正确的结果。

我现在完全被这个（实际上很简单的）问题所困扰。

有人可以引导我进入正确的方向吗？如何从boost::posix_time::ptime获取NTP日期戳的时代编号，时代偏移和分数？

编辑：RFC 5905中的计算不够准确，或者我误解了它们。感谢评论，我已将计算更改为以下内容（这次是一个完整的示例）：

#include <cmath>
#include <cstdint>
#include <iostream>

#include <boost/date_time.hpp>

int main() {
  const auto system_time =
      boost::posix_time::time_from_string("1899-12-31 00:00:00.000");

  const boost::posix_time::ptime prime_epoch{
      boost::gregorian::date{1900, 1, 1}};
  // Calculate the number of seconds from the prime epoch to the system time.
  const boost::posix_time::time_duration time_duration{prime_epoch -
                                                       system_time};

  // s is correctly determined now.
  std::int64_t s{time_duration.total_seconds()};
  if (prime_epoch > system_time) {
    // boost::posix_time::time_duration does not take the sign into account.
    s *= -1;
  }

  // TODO(wolters): The following calculations do not return the correct
  // results, but the RFC 5905 states them
  const std::int32_t era{static_cast<std::int32_t>(s / std::pow(2, 32))};
  const std::uint64_t timestamp{
      static_cast<std::uint64_t>(s - era * std::pow(2, 32))};
  // The fraction of a NTP Datestamp is measured in Attoseconds.
  // TODO(wolters): `boost::posix_time::ptime` does NOT resolve to attoseconds,
  // but doesn't the target format expect the value to be specified as
  // attoseconds? Doesn't the following depend on Boost compile options?
  const std::uint64_t fraction{
      static_cast<std::uint64_t>(time_duration.fractional_seconds())};

  std::cout << "s = " << std::dec << s << '\n';
  // TODO(wolters): This does still not match the expected results; taken from
  // Figure 4 of https://www.ietf.org/rfc/rfc5905.txt
  std::cout << "Era (expected: -1) = " << std::dec << era << '\n';
  std::cout << "Timestamp (expected: 4294880896) = " << std::dec << timestamp
            << '\n';
  std::cout << "Fraction (expected: 0) = " << std::dec << fraction << '\n';
}

s现在正确计算，但其他计算错误。我想我确实完全错过了一些重要的事情......

Answer 1

似乎我自己想出了丢失的部分。我在可重用的类ntp::Datestamp中实现了以下算法，并使用RFC 5905的参考日期对其进行了单元测试。所有测试最终都是绿色的。这是解决方案：

#include <cmath>
#include <cstdint>
#include <ctime>
#include <iostream>

#include <boost/date_time.hpp>

static std::time_t to_time(const boost::posix_time::ptime& time) {
  static const boost::posix_time::ptime epoch_time{
      boost::gregorian::date{1970, 1, 1}};
  const boost::posix_time::time_duration diff{time - epoch_time};

  return (diff.ticks() / diff.ticks_per_second());
}

int main() {
  const auto system_time =
      boost::posix_time::time_from_string("1899-12-31 00:00:00.123");
  const boost::posix_time::ptime prime_epoch{
      boost::gregorian::date{1900, 1, 1}};
  // Calculate the number of seconds from the prime epoch to the system time.
  std::time_t s{to_time(system_time) - to_time(prime_epoch)};

  const std::int32_t era{static_cast<std::int32_t>(std::floor(s / std::pow(2, 32)))};
  const std::uint32_t timestamp{
      static_cast<std::uint32_t>(s - era * std::pow(2, 32))};
  const std::uint64_t fraction{static_cast<std::uint64_t>(
      system_time.time_of_day().fractional_seconds())};

  std::cout << "s = " << std::dec << s << '\n';
  std::cout << "Era (expected: -1) = " << std::dec << era << '\n';
  std::cout << "Timestamp (expected: 4294880896) = " << std::dec << timestamp
            << '\n';
  std::cout << "Fraction (expected: 123000) = " << std::dec << fraction << '\n';
}

将boost :: posix_time :: ptime转换为NTP日期戳

1 个答案: