来自Google地方搜索框的地方照片总是达到403

时间:2017-02-23 15:47:53

标签: javascript web-services google-maps-api-3 google-places-api

我正在尝试使用Google Map Javascript API。到目前为止,我成功设置了地方搜索框并能够进行文本搜索。我得到了结果。但是,当我尝试显示地方照片时,它在我的控制台上显示错误。这方面的一个例子就是我打电话

照片[0] .getUrl({'maxWidth':400,'maxHeight':400})

我得到'https://lh3.googleusercontent.com/-DgRkkiD8btI/V52sjCeJypI/AAAAAAAFIWI/T9-7KK_VwCQPmzSgtcfOuBWogC9x4b59gCJkC/w400-h400-k/'作为它的价值。但是当我把它放在我的应用程序中时,(我正在使用样式background-image:url(xxx))我无法显示它们。我收到了403回复。但是,如果我在另一个浏览器选项卡中打开此链接,我可以看到该图像。这有点奇怪吗?有人建议我如何显示图像?

PS。我去了Google Developer Console并在那里验证了我的信用卡。我检查了API控制台上的请求数量,并且Places API请求大约是180左右。我不认为它超出了限制,但没有任何线索。

编辑:以下是我如何尝试从地方拍摄照片的示例。

<!DOCTYPE html>
<html>
  <head>
    <meta name="viewport" content="initial-scale=1.0, user-scalable=no">
    <meta charset="utf-8">
    <title>Places Searchbox</title>
    <style>
      /* Always set the map height explicitly to define the size of the div
       * element that contains the map. */
      #map {
        height: 50%;
      }
      /* Optional: Makes the sample page fill the window. */
      html, body {
        height: 100%;
        margin: 0;
        padding: 0;
      }
      #description {
        font-family: Roboto;
        font-size: 15px;
        font-weight: 300;
      }

      #infowindow-content .title {
        font-weight: bold;
      }

      #infowindow-content {
        display: none;
      }

      #map #infowindow-content {
        display: inline;
      }

      .pac-card {
        margin: 10px 10px 0 0;
        border-radius: 2px 0 0 2px;
        box-sizing: border-box;
        -moz-box-sizing: border-box;
        outline: none;
        box-shadow: 0 2px 6px rgba(0, 0, 0, 0.3);
        background-color: #fff;
        font-family: Roboto;
      }

      #pac-container {
        padding-bottom: 12px;
        margin-right: 12px;
      }

      .pac-controls {
        display: inline-block;
        padding: 5px 11px;
      }

      .pac-controls label {
        font-family: Roboto;
        font-size: 13px;
        font-weight: 300;
      }

      #pac-input {
        background-color: #fff;
        font-family: Roboto;
        font-size: 15px;
        font-weight: 300;
        margin-left: 12px;
        padding: 0 11px 0 13px;
        text-overflow: ellipsis;
        width: 400px;
      }

      #pac-input:focus {
        border-color: #4d90fe;
      }

      #title {
        color: #fff;
        background-color: #4d90fe;
        font-size: 25px;
        font-weight: 500;
        padding: 6px 12px;
      }
      #target {
        width: 345px;
      }
    </style>
  </head>
  <body>
    <input id="pac-input" class="controls" type="text" placeholder="Search Box">
    <div id="map"></div>
    <div id="place-list"></div>
    <script>
      // This example adds a search box to a map, using the Google Place Autocomplete
      // feature. People can enter geographical searches. The search box will return a
      // pick list containing a mix of places and predicted search terms.

      // This example requires the Places library. Include the libraries=places
      // parameter when you first load the API. For example:
      // <script src="https://maps.googleapis.com/maps/api/js?key=YOUR_API_KEY&libraries=places">

      function initAutocomplete() {
        var map = new google.maps.Map(document.getElementById('map'), {
          center: {lat: -33.8688, lng: 151.2195},
          zoom: 13,
          mapTypeId: 'roadmap'
        });

        // Create the search box and link it to the UI element.
        var input = document.getElementById('pac-input');
        var searchBox = new google.maps.places.SearchBox(input);
        map.controls[google.maps.ControlPosition.TOP_LEFT].push(input);

        // Bias the SearchBox results towards current map's viewport.
        map.addListener('bounds_changed', function() {
          searchBox.setBounds(map.getBounds());
        });

        var markers = [];
        // Listen for the event fired when the user selects a prediction and retrieve
        // more details for that place.
        searchBox.addListener('places_changed', function() {
          var places = searchBox.getPlaces();

          if (places.length == 0) {
            return;
          }

          // Clear out the old markers.
          markers.forEach(function(marker) {
            marker.setMap(null);
          });
          markers = [];

          // For each place, get the icon, name and location.
          var bounds = new google.maps.LatLngBounds();
          places.forEach(function(place) {
            if (!place.geometry) {
              console.log("Returned place contains no geometry");
              return;
            }
            var icon = {
              url: place.icon,
              size: new google.maps.Size(71, 71),
              origin: new google.maps.Point(0, 0),
              anchor: new google.maps.Point(17, 34),
              scaledSize: new google.maps.Size(25, 25)
            };

            var photoUrl = place.photos[0].getUrl({maxWidth: 400, maxHeight: 400});
            var img = document.createElement("img");
            img.setAttribute('src', photoUrl + "photo.jpg");
            document.getElementById('place-list').appendChild(img);

            // Create a marker for each place.
            markers.push(new google.maps.Marker({
              map: map,
              icon: icon,
              title: place.name,
              position: place.geometry.location
            }));

            if (place.geometry.viewport) {
              // Only geocodes have viewport.
              bounds.union(place.geometry.viewport);
            } else {
              bounds.extend(place.geometry.location);
            }
          });
          map.fitBounds(bounds);
        });
      }

    </script>
    <script src="https://maps.googleapis.com/maps/api/js?key=<GOOGLE_API_KEY>&libraries=places&callback=initAutocomplete"
         async defer></script>
  </body>
  </html>

1 个答案:

答案 0 :(得分:0)

我刚刚发现,如果我在localhost下渲染html,照片将会达到403.但是,如果我使用其他主机名,照片将会正确显示。我认为Google正在节省开发带宽。这个问题在生产上应该没问题,所以我不再担心这个了。 :d