我正在创建一个交互式,我在页面上有三种颜色作为div。一旦用户点击颜色,我希望图像在下一部分加载为用户选择的颜色。我创造了三种不同颜色的夹克,我需要知道如何根据他们选择的选项加载夹克的颜色。
<div id="page-colour">
<h1>About your jacket.</h1>
<h2>Select your leather jacket colour.</h2>
<div class="col-md-offset-3 col-md-2">
<div class="black-button colourButton">
<p>Black</p>
</div>
</div>
<div class="col-md-2">
<div class="brown-button colourButton">
<p>Brown</p>
</div>
</div>
<div class="col-md-2">
<div class="white-button colourButton">
<p>White</p>
</div>
</div>
</div>
<div id="page-build">
<div class="theJacket col-xs-3 col-md-9">
<img class="" src="img/black-jacket.png" class="img-responsive" alt="Black Leather Jacket" width="600" height="750"/>
</div>
</div>
这就是我加载下一页的方式:
$(document).ready(function(){
$('.intro-button').click(function(){
transition("#page-jacket","fade");
});
function transition(toPage, type){
var toPage = $(toPage),
fromPage = $("#pages .current"); // store the page that is currently showing
toPage
.addClass("current " + type + " in")
.one("msAnimationEnd animationend oAnimationEnd", function(){ // listens for when the animation has finished
fromPage.removeClass("current " + type + " out" );
toPage.removeClass(type + " in");
});
fromPage.addClass(type + " out ");
}
答案 0 :(得分:0)
有多种方法可以做到这一点。一种显而易见的方法是将图像URL存储在夹克div中的额外数据元素中:
<div class="col-md-offset-3 col-md-2">
<div class="black-button colourButton" data-imageurl="img/black-jacket.png">
<p>Black</p>
</div>
</div>
然后您更新脚本,以便当访问者点击夹克颜色时,图像会刷新:
$(document).ready(function() {
$('.colourButton').on('click', function () {
$('.theJacket img').attr('src', $(this).data('imageurl'));
});
});
或为图片提供ID,并通过其ID而非.theJacket img