我正在解析这个json数组并且我想要text
answer
对象并将其放入新列awnser2
,这是一行< / strong>我的json行,
在json中回答38和39与text
相同但是anser 40是Descriptive Awnser,我得到了非法的字符串偏移&#39; text&#39;对于 Hello Word ,我如何能够在输出中同时拥有它们?
[{"id":"38","answer":[{"option":"3","text":"HIGH"}],"type":"a"},
{"id":"39","answer":[{"option":"3","text":"LOW"}],"type":"b"},
{"id":"40","answer":["Hello Word"],"type":"c"}]
这是我的代码:
<?php
$con=mysqli_connect("localhost","root","","array");
mysqli_set_charset($con,"utf8");
// Check connection
if (mysqli_connect_errno()){
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql="SELECT `survey_answers`,us_id FROM `user_survey_start`";
if ($result=mysqli_query($con,$sql)){
while ($row = mysqli_fetch_row($result)){
$json = $row[0];
if(!is_null($json)){
$json = preg_replace('/\r|\n/','\n',trim($json));
$jason_array = json_decode($json,true);
$answers = array();
foreach ($jason_array as $data) {
if (array_key_exists('answer', $data)) {
foreach($data['answer'] as $ans){
$answers[] =$ans['text'] ;
}
}
}
if(!empty($answers)) {
$answers= implode('',$answers); /// implode yes if you got values
}
else {
$answers = 'Nothing Find'; //blank if not have any values
}
$sql3="update user_survey_start set awnser2='$answers' where us_id=".$row[1];//run update sql
echo $sql3."<br>";
mysqli_query($con,$sql3);
}
}
}
mysqli_close($con);
?>
我希望text of Awnser:
为......到39而Awnser:
为40,40是最后一个
答案 0 :(得分:1)
检查键是否设置否则指定值
foreach ($jason_array as $data) {
if (array_key_exists('answer', $data)) {
foreach($data['answer'] as $ans){
$answers[] = isset($ans['text']) ? $ans['text'] : $ans;
}
}
}