所以我有以下select声明：
requests = Request.select { |x| (x.name_rel == user || x.customer_rel == user || x.users.include?(user))
基本上，我试图获得requests user requests belongs_to :name_rel, :class_name => "User", :foreign_key => 'name_id'
belongs_to :customer_rel, :class_name => "User", :foreign_key => 'customer_id'
has_and_belongs_to_many :users
select的所有where，其中> time1.to_i == time2.to_datetime.to_i
=> true
具有以下关系：
import os, sys
import random
import pygame
from pygame.locals import *
My_red_color = (255, 0, 0)
My_blue_color = (0, 0, 255)
My_green_color = (0, 255, 0)
My_yellow_color = (255, 255, 0)
My_black_color = (0,0,0)
My_white_color = (255,255,255)
pygame.init()
APPLICATION_x_size = 800
APPLICATION_y_size = 800
screen = pygame.display.set_mode((APPLICATION_x_size, APPLICATION_y_size))
我理解x=200
y=400
pygame.display.set_caption('Piano')
pygame.mouse.set_visible(True)
#pygame.mouse.set_visible(False)
green_square= pygame.Surface(screen.get_size())
green_square.fill((0, 255, 0))
screen.blit(green_square, (0, 0))
Weeee = True
pygame.draw.rect(screen, My_white_color, (30,100,100,200))
pygame.draw.rect(screen, My_white_color, (132,100,100,200))
pygame.draw.rect(screen, My_white_color, (234,100,100,200))
pygame.draw.rect(screen, My_white_color, (336,100,100,200))
pygame.draw.rect(screen, My_white_color, (438,100,100,200))
pygame.draw.rect(screen, My_white_color, (540,100,100,200))
pygame.draw.rect(screen, My_white_color, (642,100,100,200))
pygame.draw.rect(screen, My_black_color, (81,50,100,200))
pygame.draw.rect(screen, My_black_color, (183,50,100,200))
pygame.draw.rect(screen, My_black_color, (387,50,100,200))
pygame.draw.rect(screen, My_black_color, (489,50,100,200))
pygame.draw.rect(screen, My_black_color, (591,50,100,200))
b=screen.blit(myImg, (x,y))
pygame.display.flip()
while Weeee :
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_a:
print("C")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound1.mp3')
pygame.mixer.music.play(1,0)
if event.key == pygame.K_s:
print("D")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound2.mp3')
pygame.mixer.music.play(1,0)
if event.key == pygame.K_d:
print("E")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound3.mp3')
pygame.mixer.music.play(1,0)
if event.key == pygame.K_f:
print("F")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound4.mp3')
pygame.mixer.music.play(1,0)
if event.key == pygame.K_g:
print("G")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound5.mp3')
pygame.mixer.music.play(1,0)
if event.key == pygame.K_h:
print("A")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound6.mp3')
pygame.mixer.music.play(1,0)
if event.key == pygame.K_j:
print("B")
pygame.mixer.music.load('E:\성빈\고등학교\과학전람회\pygame piano\pygame piano\sound7.mp3')
pygame.mixer.music.play(1,0)
if event.type == MOUSEBUTTONDOWN :
if event.button==1 :
print("Setting Code")
my_code=pygame.key.get_pressed()
print("My code is" + str(my_code))
if event.button == 3 :
print("Type your Code")
code_try=pygame.key.get_pressed()
if code_try==my_code :
print("Done")
else :
print("You've typed wrong code")
是一种非常糟糕的方法，但我不确定如何使{{1}}能够处理如此复杂的操作。有人能指出我正确的方向吗？
答案 0 :(得分：3)
您可以在以下情况下执行此操作
Sub Filter_Change()
Dim WS As Worksheet: Set WS = ActiveWorkbook.Worksheets("Main")
Dim PT1 As PivotTable: Set PT1 = WS.PivotTables("IncTrend")
Dim PF1 As PivotField: Set PF1 = PT1.PivotFields("[Inc Open].[Service].[Service]")
Dim Choice As String: Choice = Worksheets("Main").Range("A2").Value
With PF1
.ClearAllFilters
.CurrentPage = Choice
'.PivotFilters.Add Type:=xlCaptionEquals, Value1:=Choice
End With
End Sub