Question

我试图通过收入来获得前3名提供商，并且对于每个提供商，按字母顺序排列该提供商的前2名。这是我必须开始的基本GROUP BY查询 -

SELECT
  provider,
  title,
  SUM(customer_price)
FROM
  [integrated-myth-156821:fintest.m10]
GROUP BY
  title,
  provider
LIMIT
  25

以下是我得到的结果集：

表结构为provider | title | customer_price。

以下是我希望得到的结果的说明：

provider        title              sum(revenue)
Sony                               10000 // Top provider by revenue, limit 3
Sony            Avatar             400 // First title alphabetically, limit 2
Sony            Titanic            300
Fox                                8000
Fox             Fresh              12
Fox             Mike               800
WB                                 4500
WB              Harry              1000
WB              Potter             1200

Answer 1

以下解决方案是使用BigQuery Standard SQL

#standardSQL
WITH topProviders AS (
  SELECT provider, SUM(customer_price) AS revenue
  FROM `integrated-myth-156821.fintest.m10`
  GROUP BY provider
  ORDER BY revenue DESC 
  LIMIT 3
),
titles AS (
  SELECT provider, title, SUM(customer_price) AS revenue
  FROM `integrated-myth-156821.fintest.m10`
  GROUP BY provider, title
)
SELECT provider, title, revenue
FROM (
  SELECT p.revenue AS sort,
    STRUCT(p.provider, '' AS title, p.revenue ) AS providers, 
    ARRAY_AGG(STRUCT(t.provider, title, t.revenue) ORDER BY title LIMIT 2) AS titles
  FROM topProviders AS p 
  JOIN titles AS t 
  ON p.provider = t.provider
  GROUP BY p.provider, p.revenue 
), UNNEST(ARRAY_CONCAT([providers], titles)) 
ORDER BY sort DESC, provider, title

Answer 2

尝试以下

ROW_NUMBER() OVER(PARTITION BY provider ORDER BY title) AS pos

你可以解释一些查询吗？

此查询实际上是两个查询的联合其次（在查询的最底部）由收入提供者提供前3名

第一个为前三名中的每个提供商提供前两个标题 - 并且本身就是前三名提供商加入标题收入

以下表达式中的位置

WHERE pos < 3

然后

允许仅使用

过滤2个顶级标题

Where

在BigQuery中限制GROUP BY

2 个答案: