Question

所以这是我的代码：

main()
{
        char input[150];                                                                        //Create a variable of type char named input to store user input

        printf(" Enter a standard line: ");                                                     //Ask the user for some standard input

        if (fgets(input, 150, stdin) == NULL)                                                   //Initiate a series of checks to make sure there is valid input
        {
                puts(" End-of-File or Input Error Detected. ");                                 //If the end of the file is reached or there is a problem with input output a message
        }
        else if (input[0] == '\n')                                                              //If the user neglected to enter anything output a message
        {
                puts(" Oops! Looks like you forgot to enter something! ");
        }
        else
        {
                printf(" Here's what you entered: %s ", input);                                 //If there is valid user input echo it back to the user

                while (input[0] != '\n')
                {

                       (can I put the while loop here?)
                }
        }
}

我刚刚运行了我的代码（在Stackoverflow上由Chux提供）现在我有另一个问题。现在我可以验证是否有输入，我必须通过用ASCII代码替换某些字符，更改字母字母大小写以及换行来更换和调整输入行。

例如： 1.用户输入：google.COM/search?client
2.程序更改并打印回用户：GOOGLE.com％2FSEARCH％3FCLIENT

我该怎么做？我可以将while循环留在原处吗？

Answer 1

你不应该使用这个----＆gt; while（输入[0]！=＆＃39; \ n＆＃39;）;

让我们说你的输入[0]等于\ n这个循环永远持续，所以也许尝试像输入[i]！=＆＃39; \ n＆＃39;并增加循环中的i

如何替换和编辑字符串中的字符？

1 个答案: