Question

我经常遇到像这样的代码

  tree->Branch("Regression_Q2_RANDOM",&Regression_Q2_RANDOM,"Regression_Q2_RANDOM/F");
  tree->Branch("Regression_Q2_BEST",&Regression_Q2_BEST,"Regression_Q2_BEST/F");
  tree->Branch("Regression_Q2_WORST",&Regression_Q2_WORST,"Regression_Q2_WORST/F");
  tree->Branch("Regression_Q2_TRUE",&Regression_Q2_TRUE,"Regression_Q2_TRUE/F");
  tree->Branch("Regression_Q2_HI",&Regression_Q2_HI,"Regression_Q2_HI/F");
  tree->Branch("Regression_Q2_LO",&Regression_Q2_LO,"Regression_Q2_LO/F");

由于排长队，大多数自动格式化程序无论如何都不满意，但除此之外，我希望将函数参数对齐如下：

  tree->Branch("Regression_Q2_RANDOM",&Regression_Q2_RANDOM,"Regression_Q2_RANDOM/F");
  tree->Branch("Regression_Q2_BEST",  &Regression_Q2_BEST,  "Regression_Q2_BEST/F");
  tree->Branch("Regression_Q2_WORST", &Regression_Q2_WORST, "Regression_Q2_WORST/F");
  tree->Branch("Regression_Q2_TRUE",  &Regression_Q2_TRUE,  "Regression_Q2_TRUE/F");
  tree->Branch("Regression_Q2_HI",    &Regression_Q2_HI,    "Regression_Q2_HI/F");
  tree->Branch("Regression_Q2_LO",    &Regression_Q2_LO,    "Regression_Q2_LO/F");

这样，通过块编辑，我可以用星号替换＆符号，或者对参数的公共部分进行其他块操作。 clang-format（或许是另一个形成者）能做到吗？

奖励积分：

这可能要求太多，但最好也是字符串的公共端应该对齐：

  tree->Branch("Regression_Q2_RANDOM",&Regression_Q2_RANDOM,"Regression_Q2_RANDOM" "/F");
  tree->Branch("Regression_Q2_BEST",  &Regression_Q2_BEST,  "Regression_Q2_BEST"   "/F");
  tree->Branch("Regression_Q2_WORST", &Regression_Q2_WORST, "Regression_Q2_WORST"  "/F");
  tree->Branch("Regression_Q2_TRUE",  &Regression_Q2_TRUE,  "Regression_Q2_TRUE"   "/F");
  tree->Branch("Regression_Q2_HI",    &Regression_Q2_HI,    "Regression_Q2_HI"     "/F");
  tree->Branch("Regression_Q2_LO",    &Regression_Q2_LO,    "Regression_Q2_LO"     "/F");

使用clang-format对齐变量长度函数参数

0 个答案: