从MySQL表中返回排名

时间:2017-02-22 17:56:26

标签: mysql

这是我的表结构:

___房间:

|--------|------------|
| ROO_Id | ROO_Name   |
|--------|------------|
| 1      | Room 1     |
| 2      | Room 2     |
| 3      | Room 3     |
|--------|------------|

___预订:

|--------|------------|
| BOO_Id | BOO_RoomId |
|--------|------------|
| 1      | 1          |
| 2      | 2          |
| 3      | 2          |
|--------|------------|

___ BillableDatas:

|--------|---------------|------------|------------|
| BIL_Id | BIL_BookingId | BIL_Date   | BIL_Item   |
|--------|---------------|------------|------------|
| 1      | 1             | 2017-02-21 | Night      |
| 2      | 1             | 2017-02-22 | Night      |
| 3      | 1             | 2017-02-23 | Night      |
| 4      | 1             | 2017-02-24 | Night      |
| 5      | 2             | 2017-02-30 | Night      |
| 6      | 2             | 2017-02-31 | Night      |
| 7      | 1             | 2017-02-31 | Night      |
|--------|---------------|------------|------------|

我想知道最受欢迎的房间。

期望的结果应该是:

|------------|------------|------------|
| ROO_Name   | Night Nb   | Percentage |
|------------|------------|------------|
| Room 1     | 5          | 71.42      |
| Room 2     | 2          | 28.57      |
| Room 3     | 0          | 0          |
|------------|------------|------------|

我已经尝试过:

SELECT r.ROO_Id
     , Sum(CASE WHEN BOO_Id IS NULL THEN 0 ELSE 1 END) NumBookings
     , Concat(
         Format(
           Sum(CASE WHEN BOO_Id IS NULL THEN 0 ELSE 1 END) 
           / TotalBookings 
           * 100
         , 0) ) AS PercentageTotal
  FROM (  ___Rooms r LEFT JOIN ___Bookings b ON r.ROO_Id = b.BOO_RoomId
       ) INNER JOIN (SELECT BOO_HotelId
                          , Count(*) AS TotalBookings
                       FROM ___Bookings 
                      GROUP BY BOO_HotelId
                    ) AS TotalHotelBookings 
                 ON r.ROO_HotelId = TotalHotelBookings.BOO_HotelId
 WHERE r.ROO_HotelId = :hotel_id
 GROUP BY r.ROO_Id
 ORDER BY NumBookings DESC

但它实际上并不起作用。

有人可以帮我这个吗?

你可以使用SQL Fiddle: http://sqlfiddle.com/#!9/390b1

非常感谢。

1 个答案:

答案 0 :(得分:0)

试试这个

select Roo_Name,coalesce(bookid,0) as nightdb,coalesce(bookid * 10/Boo_Id,0) as percentage
from ___Rooms r1 
left join 
(select count(BOO_RoomId) as book, BOO_Id 
 from ___Bookings group by  BOO_Id) b1 
on r1.Roo_Id = b1.Boo_id 
left join 
(select count(Bil_BookingId) as bookid,BIL_BookingId 
from ___BillableDatas  
group by BIL_BookingId) b2 
on b2.BIL_BookingId = b1.BOO_Id group by r1.Roo_Name;

DEMO