Question

我有以下关键字：

  App For Port    [Arguments]    ${app}
  # Try to launch one app on either port, continue if it fails on port 1 and launch it on port 2, record if it fails on both.
      ${returned_port}    Set Variable    ${1}
    : FOR    ${port_num}    IN    1    2
    \    ${returned_port}    Set Variable If    ${port_num} == 2    ${2}
    \    Check App Launch    ${app}    ${port_num}
    Return From Keyword    ${returned_port}

${returned_port} Set Variable ${1}工作正常，此行后${returned_port}为1。

然而， ${returned_port} Set Variable If ${port_num} == 2 ${2}给出${returned_port}无价值。

我真的很困惑。如何设置${returned_port}为2？在此先感谢!!

Answer 1

请参阅doc：http://robotframework.org/robotframework/latest/libraries/BuiltIn.html#Set%20Variable%20If “第二个值也可以省略，在这种情况下，它的默认值为None。” 这意味着Set Variable If在第一次循环迭代期间将${returned_port}设置为None。

除此之外，您可以稍微简化一下代码：

App For Port
    [Arguments]    ${app}
    : FOR    ${port_num}    IN    1    2
    \    Check App Launch    ${app}    ${port_num}

......做同样的事。可以？如果您需要在没有条件的情况下从关键字返回值，请使用[Return] ${var}。

还有一个 - 你可以考虑使用数据驱动的方法：http://robotframework.org/robotframework/latest/RobotFrameworkUserGuide.html#data-driven-style

机器人测试框架：Set Variable如果有效？

1 个答案: