Question

问题：如何通过两个属性对data数组进行排序：

其中type始终位于顶部且
其中count始终从最小到最大。

这是我的努力：

var data = [
  {type: 'first', count: '1'},
  {type: 'second', count: '5'},
  {type: 'first', count: '2'},
  {type: 'second', count: '2'},
  {type: 'second', count: '1'},
  {type: 'first', count: '0'},
]

//Expected
var newData = [
  {type: 'first', count: '0'},
  {type: 'first', count: '1'},
  {type: 'first', count: '2'},
  {type: 'second', count: '1'},
  {type: 'second', count: '2'},
  {type: 'second', count: '5'},
]

 //**Pseudo code**//
// Will put the types on top
data.sort((a,b) => a.type === 'first' ? -1:0)

// This will sort the count 
data.sort((a,b) => a.count < b.count ? -1 ? (a.count > b.count ? 1:0)

由于count分享不同类型之间的值，我发现很难解决它。如何对这两个属性进行排序，但始终将类型保持在最顶层，并始终按从小到大的顺序计算？

Answer 1

您可以使用sort()这样的方法。

var data = [
  {type: 'first', count: '1'},
  {type: 'second', count: '5'},
  {type: 'first', count: '2'},
  {type: 'second', count: '2'},
  {type: 'second', count: '1'},
  {type: 'first', count: '0'},
]

var result = data.sort(function(a, b) {
  return ((b.type == 'first' ) - (a.type == 'first')) || (a.count - b.count)
})

console.log(result)

按两个属性排序，其中一个属性优先但具有共同值？

1 个答案: