Question

我们可以跳过/转义字符串替换中的等号（=）吗？我希望输出为“abcde”，但它打印“a = b”

set string=a=b
set string=%string:{a=b}=abcde%
echo %string%

有什么建议吗？

Answer 1

这是一种笨拙的方式：

@echo off

:: the string that contains equals
set "stringWithEquals===blah==blah==blah="
::the string you want to replace with
set replace_with=X1
echo %stringWithEquals%

call :eqrepl "%stringWithEquals%" %replace_with% res
::the result
echo %res%
goto :eof


::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
:: here are the functions you need
::
:eqrepl String Replacer [RtnVar]
setlocal
rem  the result of the operation will be stored here
set "result=#%~1#"
set "replacer=%~2"
call :strlen0 result wl
call :strlen0 replacer rl

:start

  set "part1="
  set "part2="

  rem splitting the string on two parts
  for /f "tokens=1* delims==" %%w in ("%result%") do (
   set "part1=%%w"
   set "part2=%%x"
  )

  rem calculating the count replace strings we should use
  call :strlen0 part1 p1l
  call :strlen0 part2 p2l
  set /a iteration_end=wl-p1l-p2l

  rem creating a sequence with replaced strings
  setlocal enableDelayedExpansion
  set "sequence="
  for /l %%i in (1,1,%iteration_end%) do (
   set sequence=!sequence!%replacer%
  )
  endlocal & set "sequence=%sequence%"

  rem adjust the string length
  set /a wl=wl+iteration_end*(rl-1)

  rem replacing for the current iteration
  set result=%part1%%sequence%%part2%
  rem if the second part is empty the task is over
  if "%part2%" equ "" (
   set result=%result:~1,-1%
   goto :endloop
  )


  goto :start

:endloop
endlocal & if "%~3" neq "" (set %~3=%result%) else echo %result%
exit /b

:strlen0  StrVar  [RtnVar]
  setlocal EnableDelayedExpansion
  set "s=#!%~1!"
  set "len=0"
  for %%N in (4096 2048 1024 512 256 128 64 32 16 8 4 2 1) do (
    if "!s:~%%N,1!" neq "" (
      set /a "len+=%%N"
      set "s=!s:~%%N!"
    )
  )
  endlocal&if "%~2" neq "" (set %~2=%len%) else echo %len%
exit /b

如何在字符串替换Windows命令中跳过特殊字符（=）

1 个答案: