无法找到解决方案。我现在传递一个元组列表,其中包含要插入的信息,而不是从另一个表中提取,问题就消失了。
我目前正在编写将编辑表格的代码。我有几行要插入的信息但我不断在第四个元素上获得IntegrityError
,无论顺序如何。
以下是我创建表格的方法:
CREATE TABLE segment_speed_live_layer(segment_id INTEGER PRIMARY KEY,
geom GEOMETRY(LINESTRING, 4326),
speed INTEGER);
现在,segment_id必须与另一个表匹配,因此它不是也不能是顺序的。这是功能:
def update_layer():
segment_cursor = connection.cursor()
segment_query = 'SELECT segment_id, speed FROM segment_speed_live ORDER BY segment_id'
exists_cursor = connection.cursor()
exists_query = 'SELECT EXISTS(SELECT 1 FROM segment_speed_live_layer WHERE segment_id=%s)'
insert_cursor = connection.cursor()
insert_query = """INSERT INTO segment_speed_live_layer(segment_id, geom, speed)
SELECT %(segment_id)s, geom_way, %(speed)s
FROM other_table
WHERE segment_id=%(segment_id)s"""
update_query = 'UPDATE segment_speed_live_layer SET speed=%(speed)s WHERE segment_id=%(segment_id)s'
segment_cursor.execute(segment_query)
for row in segment_cursor:
segment_id, speed = row
exists_cursor.execute(exists_query, (segment_id, ))
exists = exists_cursor.fetchone()[0]
query = update_query if exists else insert_query
print(segment_id, speed, exists)
print(insert_cursor.mogrify(query, {'segment_id': segment_id, 'speed': speed}))
insert_cursor.execute(query, {'segment_id': segment_id, 'speed': speed})
print(insert_cursor.statusmessage)
connection.commit()
如果我按速度订购,它会在第五个而不是第四个元素上失败。它似乎在较低的ID上失败了。这是测试阶段,因此我已多次删除并重新创建表,KNOW
此表中没有包含给定ID的行。
我已阅读this question和this blog post,但他们的解决方案不起作用,因为我的ID未按顺序或自动分配。
我目前唯一的想法是删除PRIMARY KEY
约束,但这并不理想。
输出参考:
(243, 69, False)
INSERT INTO segment_speed_live_layer(segment_id, geom, speed)
SELECT 243, geom_way, 69
FROM other_table
WHERE other_table.segment_id=243
INSERT 0 1
(680, 9, False)
INSERT INTO segment_speed_live_layer(segment_id, geom, speed)
SELECT 680, geom_way, 9
FROM other_table
WHERE other_table.segment_id=680
INSERT 0 1
(11599, 42, False)
INSERT INTO segment_speed_live_layer(segment_id, geom, speed)
SELECT 11599, geom_way, 42
FROM other_table
WHERE other_table.segment_id=11599
INSERT 0 1
(16399, 40, False)
INSERT INTO segment_speed_live_layer(segment_id, geom, speed)
SELECT 16399, geom_way, 40
FROM other_table
WHERE other_table.segment_id=16399
答案 0 :(得分:0)
立刻完成所有工作:
with u as (
update segment_speed_live_layer ssll
set speed = ssl.speed
from segment_speed_live ssl
where ssl.segment_id = ssll.segment_id
)
insert into segment_speed_live_layer (segment_id, geom, speed)
select segment_id, geom_way, speed
from
other_table ot
cross join
segment_speed_live ssl
where not exists (
select 1
from segment_speed_live_layer
where segment_id = ssl.segment_id
)