Question

我有一个像这样的XML文件

  <?xml version=""1.0"" encoding=""UTF-8""?>
    <SharePointFormDataResponse xmlns =""http:///"">
      <CustomerName>xyz</CustomerName>
      <PMTREV2012>
        <Transaction>
         <Title>Full payment</Title>
         <Amount>321323231</Amount>
         <Month>Feb</Month>
         <Year>2017</Year>
       </Transaction>
       <Transaction>
         <Title>Full payment</Title>
         <Amount>321323231</Amount>
         <Month>Feb</Month>
         <Year>2017</Year>
       </Transaction>
     </PMTREV2012>
     <INTREV2012>
       <Transaction>
         <TransactionType>Full payment</TransactionType>
         <Amount>321323231</Amount>
         <Month>Feb</Month>
         <Year>2017</Year>
       </Transaction>
       <Transaction>
         <TransactionType>Full payment</TransactionType>
         <Amount>321323231</Amount>
         <Month>Feb</Month>
         <Year>2017</Year>
       </Transaction>
     </INTREV2012>
   </SharePointFormDataResponse>

我正在使用以下代码将此XML转换为数据集

XmlNodeReader xmlReader = new XmlNodeReader(altitudeResponse);
dsAltitude.ReadXml(xmlReader);

当我执行此操作时，所有事务节点将合并到一个数据表中。但我希望它们基于父节点位于不同的表中。我有什么方法可以实现这个目标吗？

Answer 1

XmlNodeReader接受XmlNode作为构造函数参数。只需将相应的父节点传递给您正在填充的每个表：

XmlDocument doc = new XmlDocument();
doc.LoadXml(altitudeResponse);
var parents = doc.DocumentElement.ChildNodes.Cast<XmlNode>()
                 .Where(n => n.Name != "CustomerName");

foreach(var parentNode in parents)
{
    using (XmlNodeReader xmlReader = new XmlNodeReader(parentNode))
    {
        DataSet ds = new DataSet();
        ds.ReadXml(xmlReader);
        DataTable dt = ds.Tables[0].Copy();
        dt.TableName = parentNode.Name;
        dsAltitude.Tables.Add(dt);
    }
}

不幸的是，如果没有架构，您无法直接将数据读入DataTable - 您应该使用DataSet。

输出 - 带有两个DataTables的DataSet：

{
  "PMTREV2012": [
    {
      "Title": "Full payment",
      "Amount": "321323231",
      "Month": "Feb",
      "Year": "2017"
    },
    {
      "Title": "Full payment",
      "Amount": "321323231",
      "Month": "Feb",
      "Year": "2017"
    }
  ],
  "INTREV2012": [
    {
      "TransactionType": "Full payment",
      "Amount": "321323231",
      "Month": "Feb",
      "Year": "2017"
    },
    {
      "TransactionType": "Full payment",
      "Amount": "321323231",
      "Month": "Feb",
      "Year": "2017"
    }
  ]
}

Answer 2

试试这个..

这个有点笨重，但会产生所需的输出

 public static void ReadXMLResponse()
    {
        XDocument doc = XDocument.Load(@"D:\\Response.xml");
        DataSet ds = new DataSet();

        System.Data.DataTable dt = new System.Data.DataTable("INTREV2012");

        dt.Columns.Add("col1");
        dt.Columns.Add("Amount");
        dt.Columns.Add("Month");
        dt.Columns.Add("Year");

        dt = doc.Descendants("INTREV2012").Descendants("Transaction")
                  .Select(x =>
                  {
                      var row = dt.NewRow();
                      row.SetField<string>("col1", (string)x.Element("TransactionType").Value);
                      row.SetField<string>("Amount", (string)x.Element("Amount").Value);
                      row.SetField<string>("Month", (string)x.Element("Month").Value);
                      row.SetField<string>("Year", (string)x.Element("Year").Value);
                      return row;
                  }).CopyToDataTable();
        ds.Tables.Add(dt);

        dt = new System.Data.DataTable("PMTREV2012");

        dt.Columns.Add("col1");
        dt.Columns.Add("Amount");
        dt.Columns.Add("Month");
        dt.Columns.Add("Year");

        dt = doc.Descendants("PMTREV2012").Descendants("Transaction")
                  .Select(x =>
                  {
                      var row = dt.NewRow();
                      row.SetField<string>("col1", (string)x.Element("Title").Value);
                      row.SetField<string>("Amount", (string)x.Element("Amount").Value);
                      row.SetField<string>("Month", (string)x.Element("Month").Value);
                      row.SetField<string>("Year", (string)x.Element("Year").Value);
                      return row;
                  }).CopyToDataTable();
        ds.Tables.Add(dt);

        Console.WriteLine(ds.Tables.Count);
    }

转换XML数据集问题

2 个答案: