我有一个Spark数据框,如下所示:
id var_a var_b
-- ----- -----
01 1 2
02 3 0
我希望将值拆分为多行,如下所示
id var_name var_value
-- -------- ---------
01 var_a 1
01 var_b 2
02 var_a 3
02 var_b 0
使用Java Spark 1.6 API的最佳方法是什么?
答案 0 :(得分:1)
flatMap
是您正在寻找的功能。
它允许从一个记录生成多个记录。
答案 1 :(得分:1)
新的FlatMapFunction完成了这项工作:
import java.util.ArrayList;
import java.util.List;
import org.apache.commons.lang3.ArrayUtils;
import org.apache.spark.sql.Row;
import org.apache.spark.sql.RowFactory;
/**
* id var_a var_b
* -- ----- -----
* 01 1 2
* 02 3 0
*
* becomes
*
* id var_name var_value
* -- -------- ---------
* 01 var_a 1
* 01 var_b 2
* 02 var_a 3
* 02 var_b 0
*
*/
public class OneToManyMapFunction implements FlatMapFunction<Row, Row> {
//indexes of fields that won't change in the new rows (id)
private int[] fixedFields = {0};
//indexes of fields that will create new rows (var_a, var_b)
private int[] dynamicFields = {1, 2};
//names of the dynamic fields
private String[] dynamicFieldsName = {"var_a", "var_b"};
public OneToManyMapFunction() {}
@Override
public Iterable<Row> call(Row row) throws Exception {
List<Row> rows = new ArrayList<Row>();
Object[] fixedValues = ArrayUtils.EMPTY_OBJECT_ARRAY;
//add values that won't change in the new rows
for (int i = 0; i < fixedFields.length; i++) {
fixedValues = ArrayUtils.add(fixedValues, row.get(fixedFields[i]));
}
//create new rows
for (int i = 0; i < dynamicFields.length; i++) {
//copy fixed values (id)
Object[] values = ArrayUtils.clone(fixedValues);
//add dynamic value name (var_a or var_b)
values = ArrayUtils.add(values, dynamicFieldsName[i]);
//add dynamic value
values = ArrayUtils.add(values, row.get(dynamicFields[i]));
//create new row for dynamic val
Row newRow = RowFactory.create(values);
rows.add(newRow);
}
return rows;
}
}