Question

这是我用来在checkbox控件中添加grid的代码。也可以在最后添加这些结果。

if (!IsPostBack)
{
    cmd.CommandType = CommandType.Text;
    cmd.CommandText = " select menu_id from Menu_IDCODE where Access_Code in ('" + strParam + "')";
    cmd.Connection = con;
    sda.SelectCommand = cmd;
    sda.Fill(ds);
    for (int j = 0; j <= ds.Tables[0].Rows.Count - 1; j++)
    {
        for (int i = 0; i <= GridView1.Rows.Count - 1; i++)
        {
            CheckBox CheckBox1;
            CheckBox1 = (CheckBox)GridView1.Rows[i].FindControl("chkSelect");
            //if (CheckBox1.Checked && String = "strConnString")
            string showId = (string)GridView1.DataKeys[i].Value.ToString();

            if (ds.Tables[0].Rows[j][0].ToString() == showId)
            {
                //check box checked and correct string

                CheckBox1.Checked = true;
                break;
            }

Answer 1

更新：

gv.Rows[0].Cells[0].Controls.Add(new CheckBox());

旧代码：

<asp:GridView id="gv" runat="server">
<columns>
<asp:BoundField DataField="id" HeaderText="ID" />
<asp:TemplateField>
<ItemTemplate>
<asp:CheckBox id="cb1" runat="server" />
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:CheckBox id="cb2" runat="server" />
</ItemTemplate>
</asp:TemplateField>
<asp:TemplateField>
<ItemTemplate>
<asp:CheckBox id="cb3" runat="server" />
</ItemTemplate>
</asp:TemplateField>
</columns>
</asp:GridView>

我想在现有的复选框gridview表中添加新的复选框行，并且还想在数据库中添加新的复选框行，我将如何操作

1 个答案: