我使用这些代码SELECT id , date
FROM table1
UNION ALL
SELECT id ,k1'
但重新编码重复
FROM ork9
group by id
ORDER BY k1,k3 ASC
答案 0 :(得分:2)
union将不是一个好的选择试试这个
select table2.id,table1.date from table2
left join table1 on table1.id = table2.id
这将返回您的预期结果
答案 1 :(得分:0)
<?php
// API access key from Google API's Console
define( 'API_ACCESS_KEY', 'My_API_KEY' );
$registrationIds = array( TOKENS );
// prep the bundle
$msg = array
(
'body' => "abc",
'title' => "Hello from Api",
'vibrate' => 1,
'sound' => 1,
);
$fields = array
(
'registration_ids' => $registrationIds,
'notification' => $msg
);
$headers = array
(
'Authorization: key=' . API_ACCESS_KEY,
'Content-Type: application/json'
);
$ch = curl_init();
curl_setopt( $ch,CURLOPT_URL, 'https://fcm.googleapis.com/fcm/send' );
curl_setopt( $ch,CURLOPT_POST, true );
curl_setopt( $ch,CURLOPT_HTTPHEADER, $headers );
curl_setopt( $ch,CURLOPT_RETURNTRANSFER, true );
curl_setopt( $ch,CURLOPT_SSL_VERIFYPEER, false );
curl_setopt( $ch,CURLOPT_POSTFIELDS, json_encode( $fields ) );
$result = curl_exec($ch );
curl_close( $ch );
echo $result;
?>
这将连接两个表并从table2中获取所有记录,并且只从table1
中获取日期