我希望有一个python脚本来下载任何具有指定名称但任何文件格式的文件(可以是.txt,.csv,.pdf,.docx,.xlsx,.msg等) 目前,我有以下python代码从outlook 2013下载附件:
import win32com.client
from win32com.client import Dispatch
import datetime as date
import os.path
def attach(subject,name):
outlook = Dispatch("Outlook.Application").GetNamespace("MAPI")
inbox = outlook.GetDefaultFolder("6")
all_inbox = inbox.Items
val_date = date.date.today()
sub_today = subject
att_today = name
for msg in all_inbox:
if msg.Subject == sub_today:
break
for att in msg.Attachments:
if att.FileName == att_today:
break
att.SaveASFile(os.getcwd() + '\\' + att.FileName)
print "Mail Successfully Extracted"
如果我特定某种类型的附件,它可以正常工作。
attach('Hi','cr.txt')
但我想做这样的事情:
attach('Hi','cr.*')
所以它可以下载附件名称' cr'但是任何文件格式。
任何人都可以提出解决方法,这会有所帮助。
答案 0 :(得分:1)
希望这会有所帮助:)
import win32com.client, datetime
from win32com.client import Dispatch
import datetime as date
import os.path
def checkTime(current_message):
date_filter_unformated = datetime.date.today() - date.timedelta(days=7)
date_filter = date_filter_unformated.strftime("%m/%d/%y %I:%M:%S")
message_time = current_message.ReceivedTime
df_list = list(date_filter)
mt_list = list(str(message_time))
df_month, mt_month = int(''.join([df_list[0],df_list[1]])), int(''.join([mt_list[0],mt_list[1]]))
df_day, mt_day = int(''.join([df_list[3],df_list[4]])), int(''.join([mt_list[3],mt_list[4]]))
df_year, mt_year = int(''.join([df_list[6],df_list[7]])), int(''.join([mt_list[6],mt_list[7]]))
if mt_year < df_year:
return "Old"
elif mt_year == df_year:
if mt_month < df_month:
return "Old"
elif mt_month == df_month:
if mt_day < df_day:
return "Old"
else:
CurrentMessage(current_message)
return "Pass"
elif mt_month > df_month:
CurrentMessage(current_message)
return "Pass"
def CurrentMessage(cm):
print cm.Sender, cm.ReceivedTime
def getAttachment(msg,subject,name):
val_date = date.date.today()
sub_today = subject
att_today = name#if you want to download 'test.*' then att_today='test'
for att in msg.Attachments:
if att.FileName.split('.')[0] == att_today:
att.SaveASFile(os.getcwd() + '\\' + att.FileName)
def attach(subject,name):
outlook = Dispatch("Outlook.Application").GetNamespace("MAPI")
inbox = outlook.GetDefaultFolder("6")
all_inbox = inbox.Items
all_inbox = all_inbox.Sort("[ReceivedTime]", True)
sub_today=subject
for current_message in all_inbox:
if checkTime(current_message) == "Pass" and current_message.Subject == sub_today:
getAttachment(current_message,subject,name)
print "Mail Successfully Extracted"
答案 1 :(得分:0)
在python中使用fnmatch模块,只需检查以下文件名
如果fnmatch.fnmatch(att.FileName,att_today)
用法:attach('Hi','cr。*')
模式含义 *符合所有条件 ?匹配任何单个字符 [seq]匹配seq中的任何字符 [!seq]匹配任何不在seq中的字符