我正在尝试在我的网站上创建一个实时搜索框。我有一个数据库的XML文件。我已经完成了JavaScript部分,但我是PHP的新手,并且我在w3schools上找到了这个代码的一些问题。我的问题是如何修改以下代码,以便我只获取“name”标签的值?
PHP代码:
BufferedImage getOneFrame() {
currFrame++;
//At the 90th frame I capture that frame and save that frame
if (currFrame == 120) {
cap.read(mat2Img.mat);
mat2Img.getImage(mat2Img.mat);
Imgcodecs.imwrite("firstImage.png", mat2Img.mat);
}
cap.read(mat2Img.mat);
return mat2Img.getImage(mat2Img.mat);
}
public void splitChannels() {
IplImage firstShot = cvLoadImage("firstImage.png");
//I split the channels so that I can determine the value of the pixel range
IplImage hsv = IplImage.create( firstShot.width(), firstShot.height(), firstShot.depth(), firstShot.nChannels());
IplImage hue = IplImage.create( firstShot.width(), firstShot.height(), firstShot.depth(), CV_8UC1 );
IplImage sat = IplImage.create( firstShot.width(), firstShot.height(), firstShot.depth(), CV_8UC1 );
IplImage val = IplImage.create( firstShot.width(), firstShot.height(), firstShot.depth(), CV_8UC1 );
cvSplit( hsv, hue, sat, val, null );
//How do I get a small range of pixels of my images to determine get their HSV?
}
XML:
<?php
$xmlDoc = new DOMDocument();
$xmlDoc->load("links.xml");
$x=$xmlDoc->getElementsByTagName('link');
//get the q parameter from URL
$q=$_GET["q"];
//lookup all links from the xml file if length of q>0
if (strlen($q) > 0)
{
$hint="";
for($i=0; $i<($x->length); $i++)
{
$y=$x->item($i)->getElementsByTagName('title');
$z=$x->item($i)->getElementsByTagName('url');
if ($y->item(0)->nodeType==1)
{
//find a link matching the search text
if (stristr($y->item(0)->childNodes->item(0)->nodeValue,$q))
{
if ($hint=="")
{
$hint="<a href='" .
$z->item(0)->childNodes->item(0)->nodeValue .
"' target='_blank'>" .
$y->item(0)->childNodes->item(0)->nodeValue . "</a>";
}
else
{
$hint=$hint . "<br /><a href='" .
$z->item(0)->childNodes->item(0)->nodeValue .
"' target='_blank'>" .
$y->item(0)->childNodes->item(0)->nodeValue . "</a>";
}
}
}
}
}
// Set output to "no suggestion" if no hint were found
// or to the correct values
if ($hint == "")
{
$response="no suggestion";
}
else
{
$response=$hint;
}
//output the response
echo $response;
?>
提前感谢您的回答!我真的很感谢你的帮助!
答案 0 :(得分:1)
以下是您将如何做的示例:
<?php
$xmlDoc = new DOMDocument();
$xmlDoc->load("links.xml");
$books = $xmlDoc->getElementsByTagName("book");
//get the q parameter from URL
$q = $_GET["q"];
//lookup all links from the xml file if length of q>0
if (strlen($q) > 0) {
$hint = "";
foreach ($books as $book) {
$name = $book->getElementsByTagName("name")->item(0)->nodeValue;
$price = $book->getElementsByTagName("price")->item(0)->nodeValue;
$quantity = $book->getElementsByTagName("quantity")->item(0)->nodeValue;
echo "$name - $price - $quantity<br/>";
}
}
这将从每个图书的xml文件中打印出$name
,$price
和$quantity
。