我正在使用UDP套接字编写一个简单的程序。我需要输入患者的姓名并从数据库中检索其详细信息。患者的姓名在Doctor类中输入并发送到服务器类。然后,Server类执行查询以检索患者的详细信息。问题出在SQL语句中。当我只使用变量firstname它工作正常,但当我把第二个变量lastname时,PatientRecord变量是NULL。
服务器类:
public class Server {
public static Connection con;
public static String PatientRecords;
public static String QueryPatientInfo(String PatientDetails) throws SQLException {
System.out.print("\nNew Patient query received:\n");
String [] PatientDetArray = PatientDetails.split(",");
String firstname,lastname;
firstname = PatientDetArray[1];
lastname = PatientDetArray[2];
System.out.println("First Name: "+ firstname);
System.out.println("Last Name: "+ lastname);
Statement query = con.createStatement();
query.execute("SELECT * FROM patient WHERE FirstName = '"+firstname+"' AND LastName = '"+lastname+"' ");
ResultSet rs = query.getResultSet();
String sex;
String dob ;
String address ;
String occupation;
String phoneno ;
if(rs != null){
while (rs.next()){
sex = rs.getString("Sex");
dob = rs.getString("DOB");
address = rs.getString("Address");
occupation = rs.getString("Occupation");
phoneno = rs.getString("PhoneNo");
PatientRecords = sex + "," + dob + "," + address + "," + occupation + "," + phoneno;
}
System.out.print("Patient records successfully retrieved from database !\n\n");
return PatientRecords;
}
else {
System.out.print("Error occurred patient records not found !\n\n");
return "Error occurred patient records not found !";
}
}
public static void main(String[] args) throws IOException, SQLException {
// Connecting to database - using xampp
try
{
Class.forName("com.mysql.jdbc.Driver");
con = DriverManager.getConnection("jdbc:mysql://localhost/patientrecord", "root", "");
System.out.println("Database is connected !");
}
catch(Exception e)
{
System.out.println("Database connection error: " + e);
}
DatagramSocket serverSocket = new DatagramSocket(8008);
byte[] receiveData = new byte[1024];
byte[] sendData;
System.out.println("Server ready and waiting for clients to connect...");
while (true) {
DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
serverSocket.receive(receivePacket);
String PatientDetails = new String(receivePacket.getData());
String message;
message = QueryPatientInfo(PatientDetails);
System.out.print(message);
InetAddress IPAddress = receivePacket.getAddress();
int port = receivePacket.getPort();
sendData = message.getBytes();
DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length, IPAddress, port);
serverSocket.send(sendPacket);
}
}
}
博士班:
public class Doctor {
public static void main(String[] args) throws IOException {
BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
DatagramSocket clientSocket = new DatagramSocket();
InetAddress IPAddress = InetAddress.getByName("localhost");
// Creating array of bytes to send and receive packet
byte[] sendData;
byte[] receiveData = new byte[1024];
String request,firstName,lastName;
request = "query";
System.out.print("Patient Registration");
System.out.print("\n\nEnter Patient Details:\n");
// User input
System.out.print("First name: \n");
firstName= inFromUser.readLine();
System.out.print("Last name: \n");
lastName = inFromUser.readLine();
String PatientDetails = request + ","+ firstName + "," +lastName;
sendData = PatientDetails.getBytes();
DatagramPacket sendPacket = new DatagramPacket(sendData, sendData.length,IPAddress, 8008);
// Send data packet to server
clientSocket.send(sendPacket);
DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
//Receive data packet from server
clientSocket.receive(receivePacket);
String PatientRecords = new String(receivePacket.getData());
//System.out.print(PatientRecords);
String [] PatientDetArray = PatientRecords.split(",");
String sex,dob,address,occupation,phoneno;
sex = PatientDetArray[0];
dob = PatientDetArray[1];
address = PatientDetArray[2];
occupation = PatientDetArray[3];
phoneno = PatientDetArray[4];
System.out.println("FROM SERVER: ");
System.out.println("Details for patient : " + firstName + " " + lastName);
System.out.println("Sex: " + sex);
System.out.println("Date of birth: " +dob );
System.out.println("Address: " + address );
System.out.println("Occupation: " + occupation);
System.out.println("Phone number: " + phoneno);
clientSocket.close();
}
}
答案 0 :(得分:1)
当你的String有空格时会发生这种情况,所以为了避免这种情况你可以像这样使用trim()
:
query.execute("SELECT * FROM patient WHERE FirstName = '" + firstname.trim() +
"' AND LastName = '" + lastname.trim() + "' ");
您设置变量的方法不安全,它可能会导致语法错误或导致SQL注入,因此建议使用Prepapred Statement,这种方式更安全,因此您可以使用以下查询:
PreparedStatement preparedStatement = connection.prepareCall("SELECT * FROM patient WHERE FirstName = ? AND LastName = ? ");
preparedStatement.setString(1, firstname.trim());
preparedStatement.setString(2, lastname.trim());
ResultSet result = preparedStatement.executeQuery();
希望这可以和你合作。
答案 1 :(得分:0)
这显然意味着您下面的WHERE
条件与任何记录都不匹配,因此没有记录。尝试直接在SQL中运行查询并查看您获得的记录数。或者尝试将条件从AND
更改为OR
,这应该会给你一个想法。
WHERE FirstName = '"+firstname+"' AND LastName = '"+lastname+"'
顺便说一下,您的代码向SQL Injection
开放,因此请考虑使用参数化查询。