Question

我有三张桌子

//1
CREATE TABLE `client_domain` (
  `client_id` int(10) unsigned NOT NULL,
  `domain_id` int(10) unsigned NOT NULL,
  PRIMARY KEY (`client_id`,`domain_id`),
  KEY `FK_client_domains_domain` (`domain_id`),
  CONSTRAINT `FK_client_domain` FOREIGN KEY (`domain_id`) REFERENCES `domain` (`id`) ON DELETE CASCADE,
  CONSTRAINT `FK_client_domains_client` FOREIGN KEY (`client_id`) REFERENCES `client` (`id`) ON DELETE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf-8;
//2
CREATE TABLE `client` (
  `id` int(10) unsigned NOT NULL,
  `name` varchar(50) NOT NULL,
  `notes` text,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf-8;
//3
CREATE TABLE `domain` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `domain_name` varchar(50) DEFAULT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `IX_domain` (`domain_name`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf-8;

一切正常但是，当我尝试使用以下方法从client_domain表中删除记录时

$del = new ClientDom(array('db' => $this->_adapter));
$where[] = $del->getAdapter()->quoteInto('client_id = ?', $client);
$where[] = $del->getAdapter()->quoteInto('domain_id = ?', $domain);
$result = $del->delete($where)->toArray(); Idelete record but with an error:
SQLSTATE[42S22]: Column not found: 1054 Unknown column 'client_id' in 'where clause'...

出了什么问题......如果我'fetchAll（$ where）'也一样，但插入所有工作正常。

Answer 1

通过以下方式解决： $ del-＆GT;删除（阵列（ 'client_id =？' =＆GT; $客户端， 'domain_id =？' =＆GT; $域））; 不知道为什么，但是通过$哪里不行......如果有人知道为什么......请在这里写一下：）

与主复合键的Zend表关系 - 从表中删除记录

1 个答案: