在迭代期间更改HashMap键

时间:2010-11-21 00:25:54

标签: java set hashmap iteration

是否可以在迭代期间更改同一HashMap实例的键?因为映射条目集没有方法entry.setKey()。现在我能想到的是创建另一个HashMap ......

MultipartParsingResult parsingResult = parseRequest(request);

Map<String, String[]> mpParams = parsingResult.getMultipartParameters();
Map<String, String[]> mpParams2 = new HashMap<String, String[]>();

Iterator<Entry<String,String[]>> it = mpParams.entrySet().iterator();

while (it.hasNext()) {
    Entry<String,String[]> entry = it.next();
    String name = entry.getKey();

    if (name.startsWith(portletNamespace)) {
        mpParams2.put(name.substring(portletNamespace.length(), name.length()), entry.getValue());
    }
    else {
        mpParams2.put(name, entry.getValue());
    }
}

5 个答案:

答案 0 :(得分:17)

也许这会有所帮助:

map.put(newkey,map.remove(oldkey));

答案 1 :(得分:9)

您应该将信息保存在其他集合中,以便在迭代后对其进行修改。您只能在迭代器期间使用iterator.remove()删除条目。 HashMap合同禁止在迭代期间对其进行变更。

答案 2 :(得分:2)

您可能希望对HashMap中的键或值进行四种常见的修改。

  1. 要更改HashMap密钥,请使用get查找值对象,然后删除旧密钥并将其与新密钥一起使用。
  2. 要更改值对象中的字段,请使用get键查看值对象,然后使用其setter方法。
  3. 要完全替换值对象,只需将新值对象放在旧键上。
  4. 要使用基于旧值的值替换值对象,请使用get查找值对象,创建新对象,从旧对象复制数据,然后将新对象放在同一个键下。
  5. 像这个例子。

    static class Food
        {
        // ------------------------------ FIELDS ------------------------------
    
        String colour;
    
        String name;
    
        float caloriesPerGram;
        // -------------------------- PUBLIC INSTANCE  METHODS --------------------------
    
        public float getCaloriesPerGram()
            {
            return caloriesPerGram;
            }
    
        public void setCaloriesPerGram( final float caloriesPerGram )
            {
            this.caloriesPerGram = caloriesPerGram;
            }
    
        public String getColour()
            {
            return colour;
            }
    
        public void setColour( final String colour )
            {
            this.colour = colour;
            }
    
        public String getName()
            {
            return name;
            }
    
        public void setName( final String name )
            {
            this.name = name;
            }
    
        public String toString()
            {
            return name + " : " + colour + " : " + caloriesPerGram;
            }
    
        // --------------------------- CONSTRUCTORS ---------------------------
    
        Food( final String name, final String colour, final float caloriesPerGram )
            {
            this.name = name;
            this.colour = colour;
            this.caloriesPerGram = caloriesPerGram;
            }
        }
    
    // --------------------------- main() method ---------------------------
    
    /**
     * Sample code to TEST HashMap Modifying
     *
     * @param args not used
     */
    public static void main( String[] args )
        {
        // create a new HashMap
        HashMap<String, Food> h = new HashMap<String, Food>( 149
                /* capacity */,
                0.75f
                /* loadfactor */ );
    
        // add some Food objecs to the HashMap
        // see http://www.calorie-charts.net  for calories/gram
        h.put( "sugar", new Food( "sugar", "white", 4.5f ) );
        h.put( "alchol", new Food( "alcohol", "clear", 7.0f ) );
        h.put( "cheddar", new Food( "cheddar", "orange", 4.03f ) );
        h.put( "peas", new Food( "peas", "green", .81f ) );
        h.put( "salmon", new Food( "salmon", "pink", 2.16f ) );
    
        // (1) modify the alcohol key to fix the spelling error in the key.
        Food alc = h.get( "alchol" );
        h.put( "alcohol", alc );
        h.remove( "alchol" );
    
        // (2) modify the value object for sugar key.
        Food sug = h.get( "sugar" );
        sug.setColour( "brown" );
        // do not need to put.
    
        // (3) replace the value object for the cheddar key
        // don't need to get the old value first.
        h.put( "cheddar", new Food( "cheddar", "white", 4.02f ) );
    
        // (4) replace the value object for the peas key with object based on previous
        Food peas = h.get( "peas" );
        h.put( "peas", new Food( peas.getName(), peas.getColour(), peas.getCaloriesPerGram() * 1.05f ) );
    
        // enumerate all the keys in the HashMap in random order
        for ( String key : h.keySet() )
            {
            out.println( key + " = " + h.get( key ).toString() );
            }
        }// end main
    }
    

    我希望这会有所帮助

答案 3 :(得分:0)

最好的办法是将地图复制到一个具有所需修改的新地图,然后返回这些新地图并销毁旧地图。 我想知道这个解决方案对性能的影响是什么。

答案 4 :(得分:0)

当我需要更改地图条目的键时,我进入了此线程。 就我而言,我在Map中具有JSON表示形式,这意味着它可以保存地图或地图列表,这是代码:

private Map<String,Object> changeKeyMap(Map<String, Object> jsonAsMap) throws InterruptedException {

    Map<String,Object> mapClone = new LinkedHashMap<>();
    for (Map.Entry<String, Object> entry : jsonAsMap.entrySet()) {
        if (Thread.currentThread().isInterrupted()) throw new InterruptedException();
        Object value = entry.getValue();
        if (entry.getValue() instanceof Map) {
            value = changeKeyMap((Map) entry.getValue());
        } else if (isListOfMaps(entry.getValue())) {
            value = changeKeyListOfMaps((List<Map<String, Object>>) entry.getValue());
        }
        String changedKey = changeSingleKey(entry.getKey());
        mapClone.put(changedKey, value);
    }
    return mapClone;
}

private List<Map<String,Object>> changeKeyListOfMaps(List<Map<String,Object>> listOfMaps) throws InterruptedException {
    List<Map<String,Object>> newInnerMapList = new ArrayList<>();
    for(Object singleMapFromArray :listOfMaps){
        Map<String,Object> changeKeyedMap = changeKeyMap((Map<String, Object>) singleMapFromArray);
        newInnerMapList.add(changeKeyedMap);
    }
    return newInnerMapList;
}
private boolean isListOfMaps(Object object) {
    return object instanceof List && !((List) object).isEmpty() && ((List) object).get(0) instanceof Map;
}

private String changeSingleKey(String originalKey) {
    return originalKey + "SomeChange"
}