电话振动与屏幕锁定

时间:2017-02-21 01:23:26

标签: android android-studio countdowntimer vibrate screen-lock

我在app(在Studio中)制作计时器,当计时器达到0时,它会振动。我想这样做,以便在屏幕锁定时手机仍然振动。有什么建议吗?

这是我的主要活动:

    EditText timerWrite;
    ImageButton power;
    ImageButton check;
    TextView minsLeft;
    CountDownTimer countDownTimer = null;

    Vibrator vibe;


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.home_screen);
        vibe = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);



    timerWrite = (EditText) findViewById(R.id.timerWrite);
    power = (ImageButton) findViewById(R.id.power);
    check = (ImageButton) findViewById(R.id.check);

    minsLeft = (TextView) findViewById(R.id.minsLeft);


    power.setOnClickListener(new View.OnClickListener(){
        @Override
        public void onClick(View view){
            vibe.cancel();
            if(countDownTimer != null)
                countDownTimer.cancel();
            minsLeft.setText("stopped");
        }
        });


    check.setOnClickListener(new View.OnClickListener(){
        @Override
        public void onClick(View view) {
            vibe.cancel();
            if (countDownTimer != null)
                countDownTimer.cancel();
            String text = timerWrite.getText().toString();

                if (!text.equalsIgnoreCase("")) {
                    int mins = Integer.valueOf(text);

                    countDownTimer = new CountDownTimer(mins * 60000, 1000) {

                        @Override
                        public void onTick(long milliseconds) {
                            long minutes = milliseconds / 60000;
                            long seconds = (milliseconds / 1000) % 60;
                            minsLeft.setText(getString(R.string.minutes) + (int) (minutes) + "  seconds:" + (int) (seconds));

                        }

                        @Override
                        public void onFinish() {
                            minsLeft.setText("Are You OK?");
                            long[] pattern = {0, 1000, 2000, 100};
                            vibe.vibrate(pattern, 1);
                        }
                    }.start();
                }
            }

    });
}

谢谢!

1 个答案:

答案 0 :(得分:0)

这将超出活动生命周期,因为它将转到onPause()onStop(),因此您的代码/应用程序将无法正常工作,您正在寻找的服务将在没有这些限制的情况下运行。

https://developer.android.com/guide/components/services.html

干杯。