Question

我订阅了observable，然后将数据放入一个数组（array_item）。在第二个foreach（）中，我遍历数组以获取我的数据，但它从未执行过，因为数组仍然是空的。我的意思是执行转移到这个foreach（），而我还没有收到我的所有数据。在继续第二个foreach（）和操作数组（array_item）项之前，我怎样才能让它等到收到所有数据并在数组中。

names: any[] = [];
array_item: any[] = [];
drawtimeline(nom_cal, _hitoService, idcalbuscador) {
  this.names.forEach((ev) => {
    groups.add([{id: ev._id, content: ev.nom_calendario, cal_id: ev._id}]);
    var g = ev._id;


    for (var i = 0; i < this.names.length; i++) {
      this._hitoService.getHitos(this.names[i]._id)
          .subscribe(hito1 => {
            this.hito1 = hito1
            this.array_item.push(hito1);
          });
    }

    console.log("before 2nd foreac()");
    for (var j = 1; j < this.array_item.length; j++) {
      console.log("inside 2nd foreac()");
      this.array_item[j].forEach((item) => {
        console.log("i =  " + i + " id_item: " + this.calendarObject._id + " j =" + j);
        items.add([{
          id: i,
          group: g,
          start: item.start_datetime,
          end: item.end_datetime,
          style: itemStyle(item.design),
          className: "pepe"
        }]);
        console.log("i =  " + i + "id_item: " + this.calendarObject._id);
      });
    }

  });
}

Answer 1

任何依赖于异步进程的代码都必须在异步进程完成后才能调用。要等待所有响应，您可以使用forkJoin：RxJS Observable.forkJoin

import {Observable} from 'rxjs';

const requests = Observable.forkJoin(this.names.map(name => this._hitoService.getHitos(name._id)));
requests.subscribe(responses => { <do stuff with responses here> });

响应将是每次调用_hitoService.getHitos

的响应数组

Answer 2

import {Observable} from 'rxjs/Observable';

names: any[] = [];
array_item: any[] = [];
drawtimeline(nom_cal, _hitoService, idcalbuscador) {
  this.names.forEach((ev) => {
    groups.add([{
      id: ev._id,
      content: ev.nom_calendario,
      cal_id: ev._id
    }]);
    var g = ev._id;

    Observable.forkJoin(this.names.map(v => {

      return this._hitoService.getHitos(v._id)
        .map(hito1 => {
          this.hito1 = hito1;
          this.array_item.push(hito1);
        })
    })).subscribe(res => {

      console.log("before 2nd foreac()");
      for (var j = 1; j < this.array_item.length; j++) {
        console.log("inside 2nd foreac()");
        this.array_item[j].forEach((item) => {
          console.log("i =  " + i + " id_item: " + this.calendarObject._id + " j =" + j);
          items.add([{
            id: i,
            group: g,
            start: item.start_datetime,
            end: item.end_datetime,
            style: itemStyle(item.design),
            className: "pepe"
          }]);
          console.log("i =  " + i + "id_item: " + this.calendarObject._id);
        });
      }

    });
  })
}

代码在数据到达之前进入功能 - 如何让它在继续之前等待所有数据？

2 个答案: