有没有办法让RxSwift订阅一个返回完成块的方法?
例如,让我们有这个对象:
struct Service {
private var otherService = ...
private var initSucceeded = PublishSubject<Bool>()
var initSucceededObservale: Observable<Bool> {
return initSucceeded.asObservable()
}
func init() {
otherService.init {(success) in
self.initSucceeded.onNext( success)
}
}
}
在不同的地方有一种方法可以在服务初始化时得到通知:
service.initSucceededObservable.subscribe(onNext: {
[unowned self] (value) in
...
}).addDisposableTo(disposeBag)
service.init()
会有更简单的解决方案吗?
答案 0 :(得分:0)
我喜欢将Variables用于此类事情。另外,我建议您在这里使用课程,因为您正在跟踪独特的状态,而不仅仅是关注自己的价值观。
class Service {
private let bag = DisposeBag()
public var otherService: Service?
private var isInitializedVariable = Variable<Bool>(false)
public var isInitialized: Observable<Bool> {
return isInitializedVariable.asObservable()
}
public init(andRelyOn service: Service? = nil) {
otherService = service
otherService?.isInitialized
.subscribe(onNext: { [unowned self] value in
self.isInitializedVariable.value = value
})
.addDisposableTo(bag)
}
public func initialize() {
isInitializedVariable.value = true
}
}
var otherService = Service()
var dependentService = Service(andRelyOn: otherService)
dependentService.isInitialized
.debug()
.subscribe({
print($0)
})
otherService.initialize() // "Initializes" the first service, causing the second to set it's variable to true.
答案 1 :(得分:0)
你可以使用懒惰的属性:
lazy let initSucceededObservale: Observable<Bool> = {
return Observable.create { observer in
self.otherService.init {(success) in
observer.on(.next(success))
observer.on(.completed)
}
return Disposables.create()
}
}()
然后你可以使用:
service.init()
service.initSucceededObservable.subscribe(onNext: {
[unowned self] (value) in
...
}).addDisposableTo(disposeBag)
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