Question

我在Swift中有两个自定义数据数组。我想找到包含字典值的对象，其“Destination”等于第二个数组中的'PlaceId'。这是带有一些数据的结构，只是为了显示它们的样子。

function validate()
{
    if(isBlank(document.loginForm.loginid.value) || isNull(document.loginForm.loginid.value))
    {
        alert('Please Enter Login Id.');
        document.loginForm.loginid.focus();
        return false;
    }
    if(isBlank(document.loginForm.password.value) || isNull(document.loginForm.password.value))
    {
        alert('Please Enter Password.');
        document.loginForm.password.focus();
        return false;
    }
    var hashObj = new jsSHA("mySuperPassword", "ASCII");
    var password = hashObj.getHash("SHA-512", "HEX");

    var textval =document.loginForm.password.value; //The actual password entered by the user
    var encryptedString = $.jCryption.encrypt(textval, password); //The password is encrypted and stored

    document.loginForm.password.value = encryptedString; //The password field of the form is updated with "encrypedString" 
    document.loginForm.hiddenfield.value=password;
    document.loginForm.service_id.value=get_cookie(document.loginForm.loginid.value.toUpperCase());
    document.loginForm.action="http://pict.ethdigitalcampus.com:80/DCWeb/authenticate.do";

    return true;
}

到目前为止我得到了这个：

struct FlightInfo {
var minPrice = "648"
var carrier = "Canada Air ways"
var destination = "973973"
var origin = "983983"
}


struct PlaceData {
var cityName = "Melbourne"
var name = "Melbourne"
var cityId = "MEL"
var type = "blah"
var countryName = "Australia"
var placeId = 983983
}

但没有雪茄。作为最终结果，我怎么能得到像下面这样的东西：

    let destId = flightsArray[indexPath.row].destination as String
    let results = listOfPlaces.filter { $0.placeId == Int(destId) }

Answer 1

将您的定义用于粗略的代码，这将为您提供所需的内容：

请注意，在您的示例中，您提供了其他对象，因此只需将其转换为您的需求。

let flightsArray =
    [[ "Name": "Trenton", "destination": 403, "type":"A" ],
    [ "Name": "Houston", "destination": 288, "type":"A" ],
    [ "Name": "Boston", "destination": 244, "type":"A" ]]

var placedata = [
    ["PlaceId": "111", "title": "Leslie", "type": "station"],
    ["PlaceId": "228", "title": "Mary", "type": "station"],
    ["PlaceId": "684", "title": "Joe", "type": "station"],
    ["PlaceId": "288", "title": "Paul", "type": "station"],
    ["PlaceId": "465", "title": "Stephanie", "type": "station"],
    ["PlaceId": "569", "title": "Steve", "type": "station"],
    ["PlaceId": "663", "title": "Doug", "type": "station"],
]

for flightAt in flightsArray
{
    let places = placedata.filter({ Int($0["PlaceId"]!)! == (flightAt["destination"] as! NSNumber).intValue })

    for place in places
    {
        print ("\(place["title"])")
    }
}

Answer 2

你可以尝试一下

let flightsArray =
    [[ "Name": "", "destination": 403, "type":"A" ],
[ "Name": "", "destination": 288, "type":"A" ],
[ "Name": "", "destination": 244, "type":"A" ]] as [[String : Any]]
var placedata = [
    ["PlaceId": "111", "title": "Leslie", "type": "station"],
    ["PlaceId": "228", "title": "Mary", "type": "station"],
    ["PlaceId": "684", "title": "Joe", "type": "station"],
    ["PlaceId": "288", "title": "Paul", "type": "station"],
    ["PlaceId": "465", "title": "Stephanie", "type": "station"],
    ["PlaceId": "569", "title": "Steve", "type": "station"],
    ["PlaceId": "663", "title": "Doug", "type": "station"],
]
let destId = flightsArray[indexPath.row]["destination"] as! Int
let results = placedata.filter { $0["PlaceId"]! as String == "\(destId)" }
cell.destinationLabel.text = results[0]["placeID"]

Answer 3

首先，我会重新考虑使用Dictionary作为模型对象。使用structs，classes和enums代替它是非常可靠的。因此，您的模型看起来与此类似：

enum FlightType: String {
    case a = "A"
    case b = "B"
}

enum PlaceType: String {
    case station = "station"
    case port = "port"
}

struct Flight {
    var name: String
    var destinationId: Int
    var type: FlightType
}

struct Place {
    var identifier: Int
    var title: String
    var type: PlaceType
}

假设你有这样的数组：

let flights = [
    Flight(name: "Trenton", destinationId: 403, type: .a),
    Flight(name: "Houston", destinationId: 288, type: .a),
    Flight(name: "Boston", destinationId: 244, type: .a)
]

let places = [
    Place(identifier: 111, title: "Leslie", type: .station),
    Place(identifier: 228, title: "Mary", type: .station),
    Place(identifier: 684, title: "Joe", type: .station),
    Place(identifier: 288, title: "Paul", type: .station),
    Place(identifier: 465, title: "Stephanie", type: .station),
    Place(identifier: 569, title: "Steve", type: .station),
    Place(identifier: 663, title: "Doug", type: .station)
]

您可以像这样获得航班的目的地标题：

let destinationId = flights[indexPath.row].destinationId
let destinationTitle = places.filter{ $0.identifier == destinationId }.first?.title

检查值是否与自定义数组元素列表中的键匹配并检索其值

3 个答案: