无法弄清楚如何在传单弹出窗口中生成组件。 我尝试了两件事:
首先,将组件选择器集成到html中,但看起来好像angular不能编译它:
let my geojson = L.geoJSON(data, {
onEachFeature: (feature, layer) => {
let popup = L.popup().setContent('<app-component-detail></app-component-detail>');
layer.on({
click: () => {
layer.bindPopup(popup);
}
})
}
}).addTo(map);
当我点击地图上的某个点时,弹出窗口为空。
然后我考虑使用“resolveComponentFactory”将组件生成到ViewContainerRef中。如果我使用@ViewChild调用我的视图元素,它的效果很好:
模板:
<div #myContainer></div>
逻辑:
@ViewChild('myContainer', { read: ViewContainerRef } ) myContainer: ViewContainerRef;
private generatedComponent= this.componentFactoryResolver.resolveComponentFactory(componentDetail);
let my geojson = L.geoJSON(data, {
onEachFeature: (feature, layer) => {
layer.on({
click: () => {
this.myContainer.createComponent(this.generatedComponent);
}
})
}
}).addTo(map);
现在我想直接在弹出窗口中生成我的组件。我想我需要将ViewContainerRef设置为弹出窗口的内容。这样的事情:
@ViewChild('popup', { read: ViewContainerRef } ) popup: ViewContainerRef;
private generatedComponent= this.componentFactoryResolver.resolveComponentFactory(componentDetail);
let my geojson = L.geoJSON(data, {
onEachFeature: (feature, layer) => {
let popup = L.popup().setContent('<div #popup></div>');
layer.on({
click: () => {
layer.bindPopup(popup);
this.popup.createComponent(this.generatedComponent);
}
})
}
}).addTo(map);
编辑:以下是我将此solution转换为leaflet.js
的方式 let geojson = L.geoJSON(data, {
style: () => defaultStyle,
onEachFeature: (feature, layer) => {
let popup = L.popup();
layer.on({
click: () => {
this.zone.run( () => {
if(this.componentRef){
this.componentRef.destroy();
}
const compFactory = this.componentFactoryResolver.resolveComponentFactory(componentDetailmponent);
this.componentRef = compFactory.create(this.injector);
if (this.appRef['attachView']) { // since 2.3.0
this.appRef['attachView'](this.componentRef.hostView);
this.componentRef .onDestroy(() => {
this.appRef['detachView'](this.componentRef.hostView);
});
} else {
this.appRef['registerChangeDetector'](this.componentRef.changeDetectorRef);
this.componentRef.onDestroy(() => {
this.appRef['unregisterChangeDetector'](this.componentRef.changeDetectorRef);
});
}
let div = document.createElement('div');
div.appendChild(this.componentRef.location.nativeElement);
popup.setContent(div);
}
)
}
});
layer.bindPopup(popup);
}
});
答案 0 :(得分:2)
以下是我将此solution转换为leaflet.js的方法:
let geojson = L.geoJSON(data, {
onEachFeature: (feature, layer) => {
let popup = L.popup();
layer.on({
click: () => {
this.zone.run( () => {
if(this.componentRef){
this.componentRef.destroy();
}
const compFactory = this.componentFactoryResolver.resolveComponentFactory(componentDetailmponent);
this.componentRef = compFactory.create(this.injector);
if (this.appRef['attachView']) { // since 2.3.0
this.appRef['attachView'](this.componentRef.hostView);
this.componentRef .onDestroy(() => {
this.appRef['detachView'](this.componentRef.hostView);
});
} else {
this.appRef['registerChangeDetector'](this.componentRef.changeDetectorRef);
this.componentRef.onDestroy(() => {
this.appRef['unregisterChangeDetector'](this.componentRef.changeDetectorRef);
});
}
let div = document.createElement('div');
div.appendChild(this.componentRef.location.nativeElement);
popup.setContent(div);
}
)
}
});
layer.bindPopup(popup);
}
});
答案 1 :(得分:1)
这是一个可行的解决方案:
创建组件
component = this.resolver.resolveComponentFactory(PopupComponent).create(this.injector);
使用NG组件作为HTML:
component.location.nativeElement
例如:
this.bindPopup(this.component.location.nativeElement);
位置:
记住要添加'app.module.ts':
entryComponents: [PopupComponent]
额外
必须通知Angular有关“更改”,请致电:
component.changeDetectorRef.detectChanges()
如果要在弹出窗口中使用输入字段:
DomEvent.disableClickPropagation(this.component.location.nativeElement);
:)
答案 2 :(得分:0)
@ miguel-de-matos
const component = this.resolver.resolveComponentFactory(MyComponent).create(this.injector);
component.instance.title = 'Super Title';
component.changeDetectorRef.detectChanges();