您好我是PHP语言的初学者。我发现很难从PHP中的会话中获取/显示数据。我的登录页面工作正常,会话也正在正确地传送到用户页面。但我没有数据也没有错误。
以下是我正常工作的登录页面脚本。我没有发布带有html元素的页面,因为我在下面的脚本上使用了require_once
并且它工作正常。
<?php
session_start();
require_once 'connection.php';
$err = array();
$errcnt = 0;
if (!empty($_POST)) {
if (empty($_POST['usermail'])) {
$err['verifyerr'] = "Please insert email";
$errcnt++;
}
if (empty($_POST['password'])) {
$err['passerr'] = "Please insert password";
$errcnt++;
}
if (!empty($_POST['usermail'])) {
$userquery = "SELECT * FROM studentdetails WHERE email = '".$_POST['usermail']."'";
$userlookup = mysqli_query($connect, $userquery);
$userfetch = mysqli_fetch_assoc($userlookup);
if (empty($userfetch)) {
$err['matcherr'] = "Invalid username";
$errcnt++;
}
else {
$passquery = "SELECT * FROM studentdetails WHERE email = '".$_POST['usermail']."' AND entrykey = '".md5($_POST['password'])."'";
$passlookup = mysqli_query($connect, $passquery);
$passfetch = mysqli_fetch_assoc($passlookup);
if (empty($passfetch)) {
$err['invalidpass'] = "Invalid password";
$errcnt++;
}
else {
$_SESSION['uid'] = $_POST['usermail'];
header("Location: http://localhost/Examination/user.php");
}
}
}
}
?>
以下是user.php页面,我遇到了实际问题。
<?php
session_start();
require_once 'connection.php';
if (isset($_SESSION['uid'])) {
echo $_SESSION['uid'] . '<br>';
$query = "SELECT * FROM studentdetails WHERE id='".$_SESSION['uid']."'";
$result = mysqli_query($connect, $query);
if (!$result) {
die("Database query failed");
}
else {
echo "All ok!";
}
}
else {
echo "not connected";
}
//$queryoutput = "SELECT * FROM studentdetails WHERE id='".$_SESSION['uid']."'";
//$outquery = mysqli_connect($connect, $queryoutput);
//if (!isset($_SESSION['uid'])) {
//header("Location: http://localhost/Examination/edulogin.php");
//}
?>
<!DOCTYPE html>
<html>
<head>
<title>User Profile</title>
</head>
<body>
<h1>Welcome</h1>
<?php
while ($row = mysqli_fetch_row($result)) {
var_dump($row);
echo "<hr />";
}
?>
<!--
<h1></h1>
<table>
<tr>
<td><h4>Firstname</h4></td>
</tr>
<tr>
<td><h4>Lastname</h4></td>
</tr>
<tr>
<td><h4>Gender</h4></td>
</tr>
<tr>
<td><h4>Email</h4></td>
</tr>
<tr>
<td><h4>About You</h4></td>
</tr>
<tr>
<td><h4>Country</h4></td>
</tr>
<tr>
<td><h4>Interests</h4></td>
</tr>
<tr>
<td><h4>Image</h4></td>
</tr>
</table>
<h3>Click here to <a href="http://localhost/Examination/userout.php">Logout</a></h3>
-->
</body>
</html>
它甚至可以正确地回应会话,它会显示用户的电子邮件并回显“一切正常”。但奇怪的是没有数据被提取,因为我说没有错误。如果你知道,请告诉我一个解决方案。我将非常感激。
如果你想看看我的connection.php页面,这里是
<?php
define('DB_SERVER', 'localhost');
define('DB_USER', 'root');
define('DB_PASS', '');
define('DB_NAME', 'user_2');
$connect = mysqli_connect(DB_SERVER, DB_USER, DB_PASS, DB_NAME);
if (mysqli_connect_errno()) {
die("Connection failed: " . mysqli_connect_error() . " (" . mysqli_connect_errno() . ")");
}
?>
答案 0 :(得分:2)
因为您使用电子邮件地址设置$_SESSION['uid']
,然后尝试匹配id=email
$query = "SELECT * FROM studentdetails WHERE id='".$_SESSION['uid']."'";
如果您要分配电子邮件地址,则应尝试将选择查询更改为(类似):
$query = "SELECT * FROM studentdetails WHERE email='".$_SESSION['uid']."'";
或者分配用户ID($_SESSION['uid'] = $userfetch['id']
),然后查询:
$query = "SELECT * FROM studentdetails WHERE id='".$_SESSION['uid']."'";
您看到"All OK"
,因为没有错误,只是没有匹配的记录(因为查询可能不正确)。
......当然,请确保您保护自己免受注射!
答案 1 :(得分:-2)
首先,您需要在$_SESSION
数组中分配数据。你已经在
$_SESSION['uid'] = $_POST['usermail'];
在您的登录页面脚本中。
还要检查网址。两者(当前和请求一个)是否在同一协议上开放,即http://
?