Question

类：

[Table("department_types", Schema = "public")]
public class DepartmentTypes


[Table("departments", Schema = "public")]
    public class Department

查询：

private string BuildQuery()
            {
                return OrmConfiguration.GetSqlBuilder<DepartmentViewModel>().Format(
                    $@" SELECT {nameof(Department.Id):C},
                                {nameof(Department.Name):C},
                                {nameof(Department.TypeId):C},
                                {nameof(DepartmentTypes.Name):C} as DepartmentTypeName
                        FROM {nameof(Department):T}
                        LEFT JOIN {nameof(DepartmentTypes):T}
                        ON {nameof(Department.TypeId):C} = {nameof(DepartmentTypes.Id):C}");
            }

结果类：

public class DepartmentViewModel
    {
        public int Id { get; set; }

        public string Name { get; set; }

        public int TypeId { get; set; }

        public string DepartmentTypeName { get; set; }

    }

我想与Department和DepartmentTypes建立联接并获得DepartmentViewModel结果......

现在代替{nameof(DepartmentTypes):T}（例如）系统放置＆＃34; DepartmentViewModel＆＃34;，而不是DepartmentTypes的名称：＆＃34; department_types＆＃34;

Answer 1

我找到了答案：D。

None

如何用fastcrud编写sql代码？

1 个答案: