我不知道为什么会这样。我有一个结构可以完美地打印到文件,但是当我尝试读出该文件时,我得到的东西甚至不接近实际存在的东西。写/读部分:
int save_data(){
char enter = 0;
int response;
while(true){
printf("1. Add new player\n2. View player data\n3. Return to main");
printf("\nSelection: ");
scanf("%d", &response);
if (response == 1){
FILE* PlayerFile = fopen("players.txt","w");
int i = 0;
for (i = 0; i < 1; i++){
struct player_info aPlayer = create_player();
fprintf(PlayerFile, "Name: %s\nLevel: %d\nStrength Mod: %d\nDexterity Mod: %d\nConstitution Mod: %d\nIntelligence Mod: %d\nWisdom Mod: %d\nCharisma Mod: %d\n", aPlayer.name, aPlayer.Level, aPlayer.Str, aPlayer.Dex, aPlayer.Con, aPlayer.Int, aPlayer.Wis, aPlayer.Cha);
}
fclose(PlayerFile);
return 0;
}
else if (response == 2){
struct player_info aPlayer;{
char name[30];
int Level, Str, Dex, Con, Int, Wis, Cha;
};
FILE* PlayerFile = fopen("players.txt","r");
for (int i = 0; i < 1; i++){
struct player_info create_player;
fscanf(PlayerFile, "Name: %s\nLevel: %d\nStrength Mod: %d\nDexterity Mod: %d\nConstitution Mod: %d\nIntelligence Mod: %d\nWisdom Mod: %d\nCharisma Mod: %d\n", aPlayer.name, &aPlayer.Level, &aPlayer.Str, &aPlayer.Dex, &aPlayer.Con, &aPlayer.Int, &aPlayer.Wis, &aPlayer.Cha);
printf("\nName: %s\nLevel: %d\nStr mod: %d\nDex mod: %d\nCon mod: %d\nInt mod: %d\nWis mod: %d\nCha mod: %d\n\n", aPlayer.name, &aPlayer.Level, &aPlayer.Str, &aPlayer.Dex, &aPlayer.Con, &aPlayer.Int, &aPlayer.Wis, &aPlayer.Cha);
}
fclose(PlayerFile);
}
else if (response == 3){
false;
break;}
}
}
文件中实际存在的输入:
Name: Hamfast Drummond
Level: 9
Strength Mod: 8
Dexterity Mod: 7
Constitution Mod: 6
Intelligence Mod: 5
Wisdom Mod: 4
Charisma Mod: 3
打印上述内容时的结果:
Name: Hamfast
Level: 6422172
Str mod: 6422176
Dex mod: 6422180
Con mod: 6422184
Int mod: 6422188
Wis mod: 6422192
Cha mod: 6422196
现在,我意识到在所有变量之前,一行缺少&
,但是当我将其添加到文件中的内容时,相同的错误数字和读出是正确的,在这种情况下,但它没有打印到我放入的文件。
作为一个附带问题,如果我允许二合一,我也希望打印全名而不是第一个,但我不知道如何做到这一点
答案 0 :(得分:4)
printf希望使用[self performNewFetchedDataActionsWithDataArray:dataArray];
格式说明符的值,而scanf需要引用
此:
%d
必须
printf("\nName: %s\nLevel: %d\nStr mod: %d\nDex mod: %d\nCon mod: %d\nInt mod: %d\nWis mod: %d\nCha mod: %d\n\n", aPlayer.name, &aPlayer.Level, &aPlayer.Str, &aPlayer.Dex, &aPlayer.Con, &aPlayer.Int, &aPlayer.Wis, &aPlayer.Cha);
换句话说,你(非常)打印这些变量的地址,而不是它们的值。
答案 1 :(得分:3)
printf("\nName: %s\nLevel: %d\nStr mod: %d\nDex mod: %d\nCon mod: %d\nInt mod: %d\nWis mod: %d\nCha mod: %d\n\n", aPlayer.name, aPlayer.Level, aPlayer.Str, aPlayer.Dex, aPlayer.Con, aPlayer.Int, aPlayer.Wis, aPlayer.Cha);
您正在打印从文件中读取的内容
答案 2 :(得分:2)
使用规则%[^\n]\n
代替%s\n
。这将读取除换行符之外的所有内容,为您提供完整的名称。
&
。 &
用于获取给定变量的地址。因此,只有在使用 scanf 时才使用&
,因为我们希望将值存储在地址中。使用 printf 时只使用变量名称,因此需要使用值。答案 3 :(得分:0)
发布的代码包含许多问题,如其他答案和问题评论中所述。
这是一个干净地编译并实现建议更正的代码版本:
#include <stdio.h>
#include <stdbool.h>
struct player_info
{
char name[30];
int Level, Str, Dex, Con, Int, Wis, Cha;
};
struct player_info create_player( void );
int save_data( void );
int save_data( void )
{
//char enter = 0;
int response;
while(true)
{
printf("1. Add new player\n"
"2. View player data\n"
"3. Return to main");
printf("\nSelection: ");
if( 1 != scanf("%d", &response) )
{
perror( "scanf failed" );
return 1;
}
if (response == 1)
{
FILE* PlayerFile = fopen("players.txt","r");
if( NULL == PlayerFile )
{
perror( "fopen for truncate and write failed" );
return 1;
}
int i = 0;
struct player_info aPlayer = create_player();
fprintf(PlayerFile, "Name: %s\nLevel: %d\nStrength Mod: %d\nDexterity Mod: %d\nConstitution Mod: %d\nIntelligence Mod: %d\nWisdom Mod: %d\nCharisma Mod: %d\n", aPlayer.name, aPlayer.Level, aPlayer.Str, aPlayer.Dex, aPlayer.Con, aPlayer.Int, aPlayer.Wis, aPlayer.Cha);
fclose(PlayerFile);
return 0;
}
else if (response == 2)
{
struct player_info aPlayer;
FILE* PlayerFile = fopen("players.txt","r");
if( NULL == PlayerFile )
{
perror( "fopen for reading failed" );
return 1;
}
fscanf(PlayerFile, "Name: %s\nLevel: %d\nStrength Mod: %d\nDexterity Mod: %d\nConstitution Mod: %d\nIntelligence Mod: %d\nWisdom Mod: %d\nCharisma Mod: %d\n",
aPlayer.name,
&aPlayer.Level,
&aPlayer.Str,
&aPlayer.Dex,
&aPlayer.Con,
&aPlayer.Int,
&aPlayer.Wis,
&aPlayer.Cha);
printf("\nName: %s\nLevel: %d\nStr mod: %d\nDex mod: %d\nCon mod: %d\nInt mod: %d\nWis mod: %d\nCha mod: %d\n\n",
aPlayer.name,
aPlayer.Level,
aPlayer.Str,
aPlayer.Dex,
aPlayer.Con,
aPlayer.Int,
aPlayer.Wis,
aPlayer.Cha);
fclose(PlayerFile);
}
else if (response == 3)
{
//false;
break;
}
}
return 0;
}
但是,我强烈建议不要将所有字段标签文本放在文件中,因为它只会在尝试从程序中读取文件时产生问题。
请注意,程序在任何单个操作后都会返回,因此该文件不能包含单个播放器上的信息。