Question

我需要根据他们的类别显示帖子标题。但问题是设计。它有以下div结构。我正在使用PHP。

<div class="row">
 <div class="some-class">
  <h1> Category1 name here</h1>
   <ul>
    <li>sds</li>
    <li>sds</li>
    <li>sds</li>
   </ul>
  </div>
<div class="some-class">
  <h1> Category2 name here</h1>
   <ul>
    <li>sds</li>
    <li>sds</li>
    <li>sds</li>
   </ul>
  </div>
</div>

我知道我需要使用foreach循环，但不知道以哪种方式这是我得到的数组。

Array
(
    [0] => Array
        (
            [category_name] => Getting Started
            [id] => 2
            [question] => GS1
            [answer] => a sd asd asdjasld asd asdasd asd asd asd asdjkalsjd as
 dasd asd asd as das d. as dasd asd as
 asd asd asd asd as das as d.
a sdas d asd as dasd asd asd . asd asss
.a sd asd asd as
            [created] => 2017-02-17 05:26:15
            [slug] => gs1
            [category] => 3
        )

    [1] => Array
        (
            [category_name] => Getting Started
            [id] => 5
            [question] => GS2
            [answer] => sad as d as
            [created] => 2017-02-17 05:48:19
            [slug] => gs2
            [category] => 3
        )

    [2] => Array
        (
            [category_name] => Buying & Selling
            [id] => 3
            [question] => BS1
            [answer] => sadas dasdas d 
as d
as dasdkas;ldk;laskd; kasd 

as dlask ;ldk; kas;dk asd lka;sdk
            [created] => 2017-02-17 05:47:33
            [slug] => bs1
            [category] => 4
        )

    [3] => Array
        (
            [category_name] => Buying & Selling
            [id] => 6
            [question] => BS2
            [answer] => as das das d
            [created] => 2017-02-17 05:48:39
            [slug] => bs2
            [category] => 4
        )

    [4] => Array
        (
            [category_name] => Renting
            [id] => 4
            [question] => rent1
            [answer] => asd asd as das 
            [created] => 2017-02-17 05:48:06
            [slug] => rent1
            [category] => 6
        )

)

Answer 1

首先更改您的QUERY以使用GROUP BY返回名称和类别，试试这个..

   SELECT faq_categories.category_name, GROUP_CONCAT (site_faqs.question) FROM faq_categories JOIN site_faqs ON site_faqs.category = faq_categories.id GROUP BY faq_categories.category_name ORDER BY faq_categories.id ASC

将值作为数组获取并尝试以下代码

<div class="row">
      <?php foreach( $categoryArr as $category ) { ?>
            <div class="some-class">
              <h1> <?php echo $category['category_name']; ?> </h1>
               <ul>
               <?php $questions = explode (', ', $category['question'] ); // explode the comma seperated question value to array
                     foreach( $questions as $question ){ ?>
                   <li> <?php echo $question; ?> </li>
               <?php } ?>
               </ul>
              </div>
        <?php } ?>
</div>

Answer 2

将上次使用的category保存为$catt，然后检查下次类别名称是否相等。如果不相等意味着它显示标题并且<li>也显示。否则它只在该标题的子类别中显示<li>。

感谢Magnus。

测试：

    <div class="row"> 
 <?php
$catt = '';
foreach( $arr as $category ) { 
if($catt != $category){
?>       
 <div class="some-class">
  <h1> <?php echo $category;?></h1>
   <ul>
    <li>sds</li>
    <li>sds</li>
    <li>sds</li>
   </ul>
  </div>
<?php
} else{ ?>
    <ul>
    <li>sds</li>
    <li>sds</li>
    <li>sds</li>
   </ul>    
<?php }
$catt=$category;
 }?>
 </div>

Answer 3

希望它会对你有所帮助。

步骤：

第1步：从类别表中获取类别

第2步：根据类别ID

从帖子表中获取帖子

代码：这是示例代码，请根据您的表格和代码进行修改

<div class="row">
<?php 

 $categories = " SELECT * From Category "  ;
 foreach ( $categories as $category ) {
 $posts = " select * from posts where category = ".$category->id;
 if(count($posts) > 0) {
 ?>

  <div class="some-class">
    <h1> <?php echo $category->name; ?></h1>
    <ul>
    <?php
      foreach ( $posts as $post ) { ?>
      <li> <?php echo $post->title; ?> </li>
    <?php } ?>
   </ul>
 </div>
<?php } } ?>
</div>

注意：这就是您想要使用的方式。请根据您的代码进行修改。

只使用一次打印类别名称时使用foreach

3 个答案: