Question

JSON： -

{
"events": ["wedding", "wed"],
"event_location": ["", ""],
"event_studio": [
    ["makeover", "epica", "Raddisson"],
    ["makeover", "epica"],
    ["Raddisson", "makeover", "contours"]
],
"event_studio_location": [
    ["Ernakulam", "thrissur", "kollam"],
    ["Ernakulam", "thrissur"],
    ["kollam", "Ernakulam", "Malappuram"]
]
}

想要从json获取事件并将其存储在字符串数组中。

 String[] a=new String[responseBody.getJSONArray("events").length()];
 a=responseBody.getJSONArray("events");

显示错误不兼容的类型需要找到的字符串找到json数组

Answer 1

您无法直接将jsonarray转换为String数组。您可以使用此函数将jsonarray转换为String：

public static String[] toStringArray(JSONArray array) {
if(array==null)
    return null;

String[] arr=new String[array.length()];
for(int i=0; i<arr.length; i++) {
    arr[i]=array.optString(i);
}
return arr;
}

这将解决您的问题。

Answer 2

检查JsonString对象是即将发布的Json String，JsonObjct还是JsonArray。通过instanceof并在JSONTokener

中保存您的JsonString

如同下面的代码

Object object = new JSONTokener(jsonString).nextValue();

if (object instanceof JSONObject) 
{
  JSONObject jsonObject = (JSONObject) object;
}
else  if (object instanceof JSONArray)
{
  JSONArray jsonArray = (JSONArray) object;
}

Answer 3

尝试以下代码

try {
        JSONObject jsonObject = new JSONObject(responseBody);
        JSONArray jsonArray = jsonObject.getJSONArray("events");

        String[] arrayEvents=new String[jsonArray.length()];
        for(int i=0; i<arrayEvents.length; i++) {
            arrayEvents[i]=jsonArray.optString(i);
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

如何修复错误不兼容的类型＆＃34;必需的字符串，找到json数组＆＃34;

3 个答案: