如何使用SQL从两个表中显示CREDIT，DEBIT和BALANCE？

Question

我有两张表PAY和INVO，我希望在一个表格中显示我也按日期排序

Answer 1

首先将数据插入到临时表中，并按日期升序排列 使用以下CTE方法获得结果：

CREATE TABLE #Invoice(Name VARCHAR(100),_Date DATE,total INT)
CREATE TABLE #pay(Name VARCHAR(100),_PayDate DATE,_money INT)
CREATE TABLE #Balance(Id INT IDENTITY(1,1),Name VARCHAR(100),_PayDate    
DATE,DE INT ,CR INT ,Bal INT)

INSERT INTO #Invoice(Name ,_Date ,total )
SELECT 'mark','03/01/2015',200 UNION ALL
SELECT 'mark','01/02/2016',150 UNION ALL
SELECT 'mark','01/02/2017',200 

INSERT INTO #pay(Name ,_PayDate ,_money )
SELECT 'mark','01/01/2016',100 UNION ALL
SELECT 'mark','01/01/2017',200 

INSERT INTO #Balance ( Name ,_PayDate ,DE , CR)
SELECT Name , _Date Date , total , 0
FROM #Invoice 
UNION ALL
SELECT Name , _PayDate  Date , 0 , _money
FROM #pay 
ORDER BY Date ASC

;WITH CTEBalence(_Id , Name ,_PayDate ,DE , CR ,bal) AS
(
  SELECT Id , Name ,_PayDate ,DE , CR , CASE WHEN DE > 0 THEN DE WHEN CR > 0         
  THEN CR END
  FROM #Balance
  WHERE Id = 1
  UNION ALL
  SELECT Id ,B.Name ,B._PayDate ,B.DE , B.CR , CASE WHEN B.DE > 0 THEN (        
  C.bal + B.DE ) WHEN B.CR > 0 THEN ( C.bal - B.CR ) END
  FROM #Balance B 
  JOIN CTEBalence C ON Id > _Id AND _Id = Id - 1
)

SELECT * FROM CTEBalence

Answer 2

假设数据库是Oracle。您可以使用Oracle的分析函数SUM来实现所需的结果。

以下是基于所提供数据的解决方案。

create table pay 
( 
    name varchar(10),
    "date" date,
    money number
);

create table invo 
( 
    name varchar(10),
    "date" date,
    invo_total number
);

insert into pay values ('mark',to_date('01012016','mmddyyyy'),100);
insert into pay values ('mark',to_date('01012017','mmddyyyy'),200);

select * from pay;

NAME日期MONEY
---------- --------- ----------
标记01-JAN-16 100
标记01-JAN-17 200

insert into invo values ('mark',to_date('03012015','mmddyyyy'),200);
insert into invo values ('mark',to_date('02012016','mmddyyyy'),150);
insert into invo values ('mark',to_date('01022017','mmddyyyy'),200);

select * from invo;

姓名日期INVO_TOTAL
---------- --------- ----------
标记01-MAR-15 200
标记01-FEB-16 150
标记01-FEB-17 200

WITH trans_dtls AS
(
    SELECT rownum rn,
       name,
       "date",
       NVL(i.invo_total,0) de,
       NVL(p.money,0) cr,
       NVL(i.invo_total,0)- NVL(p.money,0) AS curr_sum
   FROM pay p
       FULL OUTER JOIN invo i USING (name,"date")
   ORDER BY name,"date"
)
SELECT 
   td1.name, 
   td1."date",
   de,
   cr,
  SUM(td1.curr_sum) over (order by td1.name,"date") bal
FROM trans_dtls td1;

姓名日期DE CR BAL
---------- --------- ---------- ---------- ------- ---
标记01-MAR-15 200 0 200
标记01-JAN-16 0 100 100
标记01-FEB-16 150 0 250
标记01-JAN-17 0 200 50
标记01-FEB-17 200 0 250