Question

我收到了一个错误：

/ accounts / tcresults的TypeError 'ImageAndUser'对象不可迭代。

我想在tc.html中显示来自数据库的用户数据，但是会发生此错误。我在views.py中写道

def tc(request):
    d = {
        'tcresults': ImageAndUser.objects.filter(user=request.user).order_by('id').last(),
    }
    return render(request, 'registration/accounts/tc.html', d)

在tc.html中

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>tc</title>
</head>
<body>
    <h2>
    {% for result in tcresults %}
    　　　{{ result.tc }}
　　 {% endfor %}
    </h2>
</body>
</html>

我想在这部分显示数据

{% for result in tcresults %}
        　　　{{ result.tc }}
 {% endfor %}

我可以理解这个错误含义，因为我指定了最新的用户数据，所以数据只有一个而且不能重复。但我不知道如何解决这个问题。怎么写呢？

Traceback说

Traceback:

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/handlers/exception.py" in inner
  39.             response = get_response(request)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  187.                 response = self.process_exception_by_middleware(e, request)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
  185.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "/Users/Desktop/accounts/views.py" in tc
  142.     return render(request, 'registration/accounts/tc.html', d)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/shortcuts.py" in render
  30.     content = loader.render_to_string(template_name, context, request, using=using)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/loader.py" in render_to_string
  68.     return template.render(context, request)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/backends/django.py" in render
  66.             return self.template.render(context)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/base.py" in render
  208.                     return self._render(context)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/base.py" in _render
  199.         return self.nodelist.render(context)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/base.py" in render
  994.                 bit = node.render_annotated(context)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/base.py" in render_annotated
  961.             return self.render(context)

File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/defaulttags.py" in render
  165.                 values = list(values)

Answer 1

该对象不可迭代，因为：

 ImageAndUser.objects.filter(user=request.user).order_by('id').last()

此过滤条件仅返回列表中的最后一个对象。一个结果元素不可迭代。

我建议您修改代码并尝试打印查询集中的项目数。

def tc(request):
    tcresults = ImageAndUser.objects.filter(user=request.user).order_by('id').last()
    print tcresults, ' queryset'
    print len(tcresults), ' length'
    d = {
        'tcresults': tcresults,
    }
    return render(request, 'registration/accounts/tc.html', d)

并像这样更新您的HTML代码：

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>tc</title>
</head>
<body>
    <h2>
    　　　{{ tcresults.tc }}
    </h2>
</body>
</html>

Answer 2

从上面的代码中删除查询中的.last()。

/ accounts / tcresults的TypeError

2 个答案: