我一直在尝试在tkinter的一个入口区域中实现验证,所以你只能输入整数:这是我现在的代码:
import tkinter as tk
class window2:
def __init__(self, master):
self.panel2 = tk.Frame(master)
self.panel2.grid()
self.button2 = tk.Button(self.panel2, text = "Quit", command = self.panel2.quit)
self.button2.grid()
self.entryfields()
def entryfields(self):
vcmd = (self.register(self.validate),
'%d', '%i', '%P', '%s', '%S', '%v', '%V', '%W')
self.text1 = tk.Entry(self.panel2, validate = 'key', validatecommand = vcmd)
self.text1.grid()
self.text1.focus()
def validate(self, action, index, value_if_allowed,
prior_value, text, validation_type, trigger_type, widget_name):
if(action=='1'):
if text in '0123456789.-+':
try:
float(value_if_allowed)
return True
except ValueError:
return False
else:
return False
else:
return True
if __name__ == "__main__":
root1 = tk.Tk()
window2(root1)
root1.mainloop()
部分代码也来自此论坛。我认为这是一个我遗漏的继承问题。
答案 0 :(得分:0)
要对浮点数进行验证,只需在允许编辑(%P
)时为验证命令指定值即可。尝试将其转换为浮点数,如果失败则返回False
,如果成功则返回True
。
例如:
class window2:
...
def entryfields(self):
vcmd = (self.panel2.register(self.validate), '%P')
self.text1 = tk.Entry(self.panel2, validate = 'key', validatecommand = vcmd)
self.text1.grid()
self.text1.focus()
def validate(self, value_if_allowed):
if value_if_allowed == "":
# allow null entries so the user can delete everything
# before entering a value if they wish.
return True
try:
float(value_if_allowed)
return True
except ValueError:
self.panel2.bell()
return False
有关条目小部件验证的详细信息,请参阅以下答案:https://stackoverflow.com/a/4140988/7432