Question

代码输出＆＃34;我将前往洛杉矶。旅程将有300英里。我们需要停2站。＆＃34;当它应该拉出复数或单数的单词＆＃34;停止＆＃34;取决于我的IF语句中定义的数字（在这种情况下，它应该是复数）。由于我构建课程的方式，我猜测IF并不像我预期的那样工作。任何帮助修复它将不胜感激。

class trip {

  public $destination;
  public $distance;
  public $unit;
  public $stops = null;
  public $transport = null;

  function __construct($destination, $distance, $unit, $stops, $transport) {
    $this->destination = $destination;
    $this->distance = $distance;
    $this->unit = $unit;
    $this->stops = $stops;
    $this->transport = $transport;
  }

  function getTrip() {
    $a = "I will be going to " . $this->destination . ". ";
    $a .= "The journey will be a distance of " . $this->distance . " " . $this->unit . ". ";
    $a .= "We will need to make " . $this->stops;
    if ($this->stops = 1) {
      $a .= " stop.";
    } else {
      $a .= " stops.";
    }
    $a .= "\n";
    echo $a;
  }
}

$first = new trip('Los Angeles',300,'miles',2,'airplane');
$first->getTrip();

Answer 1

你好像忽略了一个小细节。

if ($this->stops = 1)

应该是

if ($this->stops == 1)

Answer 2

您的IF声明似乎错了。事实上，它应该是：

if( $this->stops == 1){ ...

你必须使用两个==符号进行比较，否则就是一个作业。所以在你的情况下，一个=符号不会真正测试你期望的条件。

IF语句无法正确解析

2 个答案: