无法使用include从另一个php文件执行数据库语句

Question

将类定义添加到StoreUser.php文件并从store.php文件中调用它后，我做错了什么，因为它不起作用？它在文件StoreUser.php中运行良好，没有类定义和函数，见下文。     

$dbhost = "localhost";
$dbname = "riskinarviointilomake";
$dbuser = "root";
$dbpass = "";
//private $email;

if(isset($_GET["email"])){

$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}


if (!( $stmt = $conn->prepare("INSERT INTO users(unique_id,email,
  encrypted_password) VALUES(?,?,?)"))){

    echo "Table creation failed: (" . $conn->errno . ") " . $conn->error;
}
    $stmt->bind_param('sss', $unique_id,$email,$password);

    $unique_id=123457764;
    $password="df12467hh";  

    $result = $stmt->execute();
    $stmt->close();
    $conn->close();


   }




  ?>      

这不起作用

class StoreUser{

$dbhost = "localhost";
$dbname = "riskinarviointilomake";
$dbuser = "root";
$dbpass = "";
//private $email;


public function store($email){
$conn = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}


if (!( $stmt = $conn->prepare("INSERT INTO users(unique_id,email, encrypted_password) VALUES(?,?,?)"))){

    echo "Table creation failed: (" . $conn->errno . ") " . $conn->error;
}
    $stmt->bind_param('sss', $unique_id,$email,$password);

    $unique_id=123457764;
    $password="df12467hh";  

    $result = $stmt->execute();
    $stmt->close();
    $conn->close();


 }

}

    <?php

    include 'StoreTest.php';

   if(isset($_GET['email'])){
     $email = $_GET['email'];
     $store = new StoreTest();
     $store->store($email);


   }


 ?>