我想做这样的事情:在一个循环中,第一次迭代将一些内容写入名为file0.txt的文件,第二次迭代file1.txt等等,只需增加数量。
FILE *img;
int k = 0;
while (true)
{
// here we get some data into variable data
file = fopen("file.txt", "wb");
fwrite (data, 1, strlen(data) , file);
fclose(file );
k++;
// here we check some condition so we can return from the loop
}
答案 0 :(得分:16)
int k = 0;
while (true)
{
char buffer[32]; // The filename buffer.
// Put "file" then k then ".txt" in to filename.
snprintf(buffer, sizeof(char) * 32, "file%i.txt", k);
// here we get some data into variable data
file = fopen(buffer, "wb");
fwrite (data, 1, strlen(data) , file);
fclose(file );
k++;
// here we check some condition so we can return from the loop
}
答案 1 :(得分:7)
在C ++中使用它的另一种方法:
#include <iostream>
#include <fstream>
#include <sstream>
int main()
{
std::string someData = "this is some data that'll get written to each file";
int k = 0;
while(true)
{
// Formulate the filename
std::ostringstream fn;
fn << "file" << k << ".txt";
// Open and write to the file
std::ofstream out(fn.str().c_str(),std::ios_base::binary);
out.write(&someData[0],someData.size());
++k;
}
}
答案 2 :(得分:2)
FILE *img;
int k = 0;
while (true)
{
// here we get some data into variable data
char filename[64];
sprintf (filename, "file%d.txt", k);
file = fopen(filename, "wb");
fwrite (data, 1, strlen(data) , file);
fclose(file );
k++;
// here we check some condition so we can return from the loop
}
答案 3 :(得分:2)
所以使用sprintf创建文件名:
char filename[16];
sprintf( filename, "file%d.txt", k );
file = fopen( filename, "wb" ); ...
(虽然这是C解决方案,因此标签不正确)
答案 4 :(得分:1)
我以下面的方式完成了这个。请注意,与其他一些示例不同,这实际上将按照预期处理器包含的方式进行编译和正常运行,而不进行任何修改。下面的解决方案迭代了50个文件名。
int main(void)
{
for (int k = 0; k < 50; k++)
{
char title[8];
sprintf(title, "%d.txt", k);
FILE* img = fopen(title, "a");
char* data = "Write this down";
fwrite (data, 1, strlen(data) , img);
fclose(img);
}
}