Question

我正在尝试将字符串int和布尔值的文件作为对象块读入数组列表中。字符串值很好地进入数组列表，它的布尔值我遇到了麻烦。每当我遇到变量＆＃39; active＆＃39;就会出现不匹配异常。请帮忙！如果块是向导的文本文件按此顺序排列名字（字符串）位置（字符串） active（boolean）...我遇到问题的那个技能水平（int）友善（int）

我包含了驱动程序类以及包含该类的Witch类变量＆＃39;活跃＆＃39;原本。



Driver class that adds objects to the array list based on what the scanner 
reads from the file
    package project2;

    import java.util.Scanner;
    import java.io.File;
    import java.io.FileNotFoundException;
    import java.util.ArrayList;

    public class Project2 {

      public static void main(String[] args) {

        Scanner inputFileScanner1 = null;

        //file name
        String listFile = "list.txt";

        // Check to see if file exists
        try {
          inputFileScanner1 = new Scanner(new File(listFile));

        } catch (FileNotFoundException e) {

          System.out.println("Error opening file.");
          System.exit(1);
        }

        //create Individuals arraylist and Location arraylist
        ArrayList < Individual > Individual = new ArrayList < > ();
        ArrayList < String > Location = new ArrayList < > ();

        //declare variables to read file contents into the arraylist
        String wizName, witchName, individualName, location, position, 

        profession = null, line = null;
        int wizLevel, witchSkillLevel, friendliness;
        boolean active;

        //while there is a next line, if the line equals Wizard, the next                                        four lines
        // are wizard name, location, position and level
        while (inputFileScanner1.hasNext()) {
          line = inputFileScanner1.nextLine();
          if (line.trim().equals("Wizard")) {

            wizName = inputFileScanner1.nextLine().trim();
            location = inputFileScanner1.nextLine().trim();
            position = inputFileScanner1.nextLine().trim();
            wizLevel = inputFileScanner1.nextInt();

            //create wizard object
            Individual wizard = new Wizard(wizName, location, position, profession, wizLevel);

            //fill arraylist with wizard objects
            Individual.add(wizard);
            Location.add(location);

          } //if the next line is Witch, the next five lines are
          // witch name, location, yes/no active, skill level, and friendliness
          //in that order
          else if (line.trim().equals("Witch")) {
            witchName = inputFileScanner1.nextLine().trim();
            location = inputFileScanner1.nextLine().trim();
            active = inputFileScanner1.nextBoolean();
            witchSkillLevel = inputFileScanner1.nextInt();
            friendliness = inputFileScanner1.nextInt();

            //create witch object
            Individual witch = new Witch(witchName, location, profession, witchSkillLevel, friendliness, active);

            //fill the arraylist with witch objects
            Individual.add(witch);
            Location.add(location);
          } else {

            profession = line.trim();
            individualName = inputFileScanner1.nextLine().trim();
            location = inputFileScanner1.nextLine().trim();

            Individual i = new Individual(profession, individualName, location);

            Individual.add(i);
            Location.add(location);
          }
          java.util.Collections.sort(Individual);
          java.util.Collections.sort(Location);

        }

        System.out.println("List of friends and possible allies: " + Location);

        inputFileScanner1.close();

      }

    }

//包含文本文件中值的Witch类。 active是布尔值我遇到了麻烦 package project2;

Driver class that adds objects to the array list based on what the scanner 
reads from the file
    package project2;

    import java.util.Scanner;
    import java.io.File;
    import java.io.FileNotFoundException;
    import java.util.ArrayList;

    public class Project2 {

      public static void main(String[] args) {

        Scanner inputFileScanner1 = null;

        //file name
        String listFile = "list.txt";

        // Check to see if file exists
        try {
          inputFileScanner1 = new Scanner(new File(listFile));

        } catch (FileNotFoundException e) {

          System.out.println("Error opening file.");
          System.exit(1);
        }

        //create Individuals arraylist and Location arraylist
        ArrayList < Individual > Individual = new ArrayList < > ();
        ArrayList < String > Location = new ArrayList < > ();

        //declare variables to read file contents into the arraylist
        String wizName, witchName, individualName, location, position, 

        profession = null, line = null;
        int wizLevel, witchSkillLevel, friendliness;
        boolean active;

        //while there is a next line, if the line equals Wizard, the next                                        four lines
        // are wizard name, location, position and level
        while (inputFileScanner1.hasNext()) {
          line = inputFileScanner1.nextLine();
          if (line.trim().equals("Wizard")) {

            wizName = inputFileScanner1.nextLine().trim();
            location = inputFileScanner1.nextLine().trim();
            position = inputFileScanner1.nextLine().trim();
            wizLevel = inputFileScanner1.nextInt();

            //create wizard object
            Individual wizard = new Wizard(wizName, location, position, profession, wizLevel);

            //fill arraylist with wizard objects
            Individual.add(wizard);
            Location.add(location);

          } //if the next line is Witch, the next five lines are
          // witch name, location, yes/no active, skill level, and friendliness
          //in that order
          else if (line.trim().equals("Witch")) {
            witchName = inputFileScanner1.nextLine().trim();
            location = inputFileScanner1.nextLine().trim();
            active = inputFileScanner1.nextBoolean();
            witchSkillLevel = inputFileScanner1.nextInt();
            friendliness = inputFileScanner1.nextInt();

            //create witch object
            Individual witch = new Witch(witchName, location, profession, witchSkillLevel, friendliness, active);

            //fill the arraylist with witch objects
            Individual.add(witch);
            Location.add(location);
          } else {

            profession = line.trim();
            individualName = inputFileScanner1.nextLine().trim();
            location = inputFileScanner1.nextLine().trim();

            Individual i = new Individual(profession, individualName, location);

            Individual.add(i);
            Location.add(location);
          }
          java.util.Collections.sort(Individual);
          java.util.Collections.sort(Location);

        }

        System.out.println("List of friends and possible allies: " + Location);

        inputFileScanner1.close();

      }

    }

文字档案： enter image description here

Answer 1

当你拉入你的布尔变量时，做这样的事情。

if(inputFileScanner1.nextLine().trim().equals("yes"))
{
    active = true;
}
else
{
    active = false;
}

Answer 2

好的，问题是该文件包含字符串yes和no，这些字符串无法直接解析为布尔值（应为true或false）。< / p>

如果你能以某种方式更改原始数据文件，我建议使用两个true和false关键字，否则@Sendrick Jefferson解决方案将完成这项工作（风险自负：每一个错字，例如＆＃34; ye＆＃34;，将被翻译成错误的。）

将具有布尔值的文本文件作为对象读入数组列表

2 个答案: