对于以下HTML,我想解析它并使用Nokogiri得到以下结果。
event_name = "folk concert 2"
event_link = "http://www.douban.com/event/12761580/"
event_date = "20th,11,2010"
我知道doc.xpath('//div[@class="nof clearfix"]')
可以获取每个div
元素,但我应该如何继续获取event_name
之类的每个归因,尤其是date
?
HTML
<div class="nof clearfix">
<h2><a href="http://www.douban.com/event/12761580/">folk concert 2</a> <span class="pl2"> </span></h2>
<div class="pl intro">
Date:25th,11,2010<br/>
</div>
</div>
<div class="nof clearfix">
<h2><a href="http://www.douban.com/event/12761581/">folk concert </a> <span class="pl2"> </span></h2>
<div class="pl intro">
Date:10th,11,2010<br/>
</div>
</div>
答案 0 :(得分:17)
我不知道xpaths,我更喜欢使用css选择器,它们对我来说更有意义。 This tutorial可能对您有用。
require 'rubygems'
require 'nokogiri'
require 'pp'
Event = Struct.new :name , :link , :date
doc = Nokogiri::HTML DATA
events = doc.css("div.nof.clearfix").map do |eventnode|
name = eventnode.at_css("h2 a").text.strip
link = eventnode.at_css("h2 a")['href']
date = eventnode.at_css("div.pl.intro").text.strip
Event.new name , link , date
end
pp events
__END__
<div class="nof clearfix">
<h2><a href="http://www.douban.com/event/12761580/">folk concert 2</a> <span class="pl2"> </span></h2>
<div class="pl intro">
Date: 25th,11,2010<br/>
</div>
</div>
<div class="nof clearfix">
<h2><a href="http://www.douban.com/event/12761581/">folk concert </a> <span class="pl2"> </span></h2>
<div class="pl intro">
Date: 10th,11,2010<br/>
</div>
</div>
输出:
[#<struct Event
name="folk concert 2",
link="http://www.douban.com/event/12761580/",
date="Date: 25th,11,2010">,
#<struct Event
name="folk concert",
link="http://www.douban.com/event/12761581/",
date="Date: 10th,11,2010">]