Question

我试图遍历一个列表并将这些项目与一个人输入的内容进行比较，然后做出决定。我的逻辑出错的任何想法？

user = input("Enter your password: ")
passwords = ["pa$$w0rd", "password123", "scr1pt1ng", "F0r3n51c5",    "123456"];

for n in passwords:
    if n == user:
        print("Found", n)
        break
    else:
        print(user, "Not Found")

Answer 1

您需要阅读有关python2和python3之间差异的更多信息。

在你的代码中使用python3样式：print(something)，因为python2样式应该是print "something"; input vs raw_input

所以你的版本是Python3

我不使用python2，但它应该是：

user = raw_input("Enter your password: ")  # input changed to raw_input
passwords = ["pa$$w0rd", "password123", "scr1pt1ng", "F0r3n51c5",    "123456"];

for n in passwords:
    if n == user:
        print "Found", n
        break
    else:
        print user, "Not Found"

使用循环＆amp ;;比较列表中的项目条件陈述

1 个答案: